flutter_bloc 库中的存储库提供程序在推送新路由时不提供存储库

Dan*_*T29 4 dart flutter bloc

我正在使用 flutter_bloc 库来构建我的应用程序。除了 BlocProvider 之外,我还使用了 Repository Provider,因为我将在整个应用程序中广泛使用特定的存储库。但是我在上下文方面遇到了问题。以下是我的代码片段:

main.dart

void main() async {
  .......
  appRepository _appRepository = AppRepository();
  SystemChrome.setPreferredOrientations([DeviceOrientation.portraitUp])
      .then((_) {
    runApp(
      BlocProvider(
        builder: (context) =>
            AuthenticationBloc(appRepository: _appRepository)..dispatch(AppStarted()),
        child: App(appRepository: _appRepository,),
      ),
    );
  });
}

class App extends StatelessWidget {

............
  @override
  Widget build(BuildContext context) {
    return MaterialApp(
      debugShowCheckedModeBanner: false,
      home: BlocBuilder<AuthenticationBloc, AuthenticationState>(
        builder: (BuildContext context, AuthenticationState state) {
       .....
          if (state is AuthenticationUnauthenticated) {
            return SafeArea(
              top: false,
              bottom: false,
              child: RepositoryProvider(
                builder: (context) => _appRepository,
                child: LoginPage(firebaseMessaging: _firebaseMessaging),
              ),
            );
          }
      ......

        },
      ),
    );
  }
}
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登录表单中的注册按钮:

register_button.dart

class RegisterButton extends StatelessWidget {
  final FirebaseMessaging _firebaseMessaging;

  RegisterButton({
    Key key,
    @required FirebaseMessaging firebaseMessaging,
  })  : assert(firebaseMessaging != null),
        _firebaseMessaging = firebaseMessaging,
        super(key: key);

  @override
  Widget build(BuildContext context) {
    return Row(
      mainAxisAlignment: MainAxisAlignment.center,
      children: <Widget>[
        Text("Don't have an account?", style: TextStyle(color: Colors.black)),
        SizedBox(width: 4.0),
        GestureDetector(
          child: Text("Register here!",
              style: TextStyle(
                  color: Color(0xFF585B8D), fontWeight: FontWeight.w500)),
          onTap: () {
            Navigator.of(context).push(
              MaterialPageRoute(builder: (context) {
                return RegisterPage(
                  firebaseMessaging: _firebaseMessaging,
                );
              }),
            );
          },
        )
      ],
    );
  }
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register_page.dart

class RegisterPage extends StatelessWidget {
  final FirebaseMessaging _firebaseMessaging;

  RegisterPage({
    Key key,
    @required FirebaseMessaging firebaseMessaging,
  })  : assert(firebaseMessaging != null),
        _firebaseMessaging = firebaseMessaging,
        super(key: key);

  @override
  Widget build(BuildContext context) {
    return Scaffold(
      body: BlocProvider(
        builder: (context) => RegisterBloc(
          appRepository: RepositoryProvider.of<AppRepository>(context),
          firebaseMessaging: _firebaseMessaging,
        ),
        child: RegisterForm(),
      ),
    );
  }
}
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题:

当我单击登录表单上的注册按钮时出现错误,该按钮显示以下内容:

No ancestor could be found starting from the context that was passed to RepositoryProvider.of<AppRepository>().

This can happen if:
1. The context you used comes from a widget above the RepositoryProvider.
2. You used MultiRepositoryProvider and didn't explicity provide the RepositoryProvider types.

Good: RepositoryProvider<AppRepository>(builder: (context) => AppRepository())
Bad: RepositoryProvider(builder: (context) => AppRepository()).

The context used was: BlocProvider<RegisterBloc>(dirty, state: _DelegateWidgetState#a87b2(lifecycle state: created))
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为什么我收到这个错误?如果我将存储库提供程序作为 blocprovider 的子项和应用程序作为主函数中的子存储库提供程序,然后在 App() 中删除单个存储库提供程序,则此问题似乎已解决。我猜问题是从按钮推动材料页面路线。我不认为我了解上下文或提供程序在 Flutter 中究竟是如何工作的。我认为提供者会查找存储库/块的小部件树,推送路由是否会破坏这种连续性?

Gia*_*ode 9

当您使用Navigator.of(context).pushNavigator.of(context).pushNamed推送的小部件不是调用Navigator.of(context).pushor 的Navigator.of(context).pushNamed小部件的子部件时,此小部件是Navigator包含给定的最接近实例的子部件context,在您的情况下Navigator是由MaterialApp,因此如果您想提供RepositoryBloc不同的是routes,the Providermust be a parent of the Navigator,在你的情况下必须是MaterialApp.