从Django中基于类的通用视图向ModelForm发送request.user对象

Question

因此,我的目标是能够在ModelForm中过滤ModelChoiceField查询集,只包含request.user创建的Places.

我的ModelForm很简单:

class PlaceEventForm(models.ModelForm):
    class Meta:
        model = Event

我希望能够添加如下内容:

def __init__(self, *args, **kwargs):
    super(PlaceEventForm, self).__init__(*args, **kwargs)
    self.fields['place'].queryset = Place.objects.filter(created_by=request.user)

但是,我似乎找不到在ModelForm中访问请求的方法.

我的观点是这样的:

class PlaceEventFormView(CreateView):
    form_class = PlaceEventForm
    template_name = 'events/event_create.html'

    @method_decorator(login_required)
    def dispatch(self, *args, **kwargs):
        return super(PlaceEventFormView, self).dispatch(*args, **kwargs)

我不确定这是否接近我应该做的,但我试过:

def get_form_kwargs(self):
    kwargs = super(PlaceEventFormView, self).get_form_kwargs()
    kwargs.update({'place_user': self.request.user})
    return kwargs

但是我得到了错误:init()得到了一个意外的关键字参数'place_user'

关于这个的任何想法？或者,任何人都可以想到一种方法来过滤我的ModelChoiceField在视图中,而无需将我的请求传递给ModelForm？

Answer 1

你需要弹出键user从kwargs在PlaceEventForm.__init__()方法,以防止它去ModelForm.__init__()的方法:

views.py:

class PlaceEventFormView(CreateView):
    form_class = PlaceEventForm
    template_name = 'events/event_create.html'

    @method_decorator(login_required)
    def dispatch(self, *args, **kwargs):
        return super(PlaceEventFormView, self).dispatch(*args, **kwargs)

    def get_form_kwargs(self):
        kwargs = super(PlaceEventFormView, self).get_form_kwargs()
        kwargs.update({'place_user': self.request.user})
        return kwargs

forms.py:

class PlaceEventForm(models.ModelForm):
    class Meta:
        model = Event

    def __init__(self, *args, **kwargs):
        user = kwargs.pop('place_user')
        # now kwargs doesn't contain 'place_user', so we can safely pass it to the base class method
        super(PlaceEventForm, self).__init__(*args, **kwargs)
        self.fields['place'].queryset = Place.objects.filter(created_by=user)