BPu*_*ear 0 android casting class ksoap2
我目前正在尝试使用常规的Ksoap实现从我的webservice中检索一个数组.但是,当尝试访问此数组时,我收到以下logcat错误:
04-27 00:27:01.772: ERROR/AndroidRuntime(530): Caused by: java.lang.RuntimeException: Unable to
start activity ComponentInfo{android.waiter/android.waiter.TablesActivity}:
java.lang.ClassCastException: org.ksoap2.serialization.SoapPrimitive
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看来,由于某种原因,Soap与我投射我的房产价值的方式并不相符.附件是问题代码(和相关方法)
public static TableDTO[] RetrieveFromSoap(SoapObject soap)
{
TableDTO[] tables = new TableDTO[soap.getPropertyCount()];
for (int i = 0; i < tables.length-1; i++) {
SoapObject pii = (SoapObject) soap.getProperty(i);
TableDTO table = new TableDTO();
table.setTableID(Integer.parseInt(pii.getProperty(0).toString()));
table.setCapacity(Integer.parseInt(pii.getProperty(1).toString()));
table.setStatusFlag(pii.getProperty(2).toString());
table.setCurrentWaiter(pii.getProperty(3).toString());
tables[i] = table;
}
return tables;
}
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TableDTO信息:
@Override
public Object getProperty(int arg0) {
switch(arg0)
{
case 0:
return TableID;
case 1:
return Capacity;
case 2:
return StatusFlag;
case 3:
return currentWaiter;
}
return null;
}
@Override
public int getPropertyCount() {
// TODO Auto-generated method stub
return 3;
}
@Override
public void getPropertyInfo(int arg0, Hashtable arg1, PropertyInfo info) {
switch(arg0){
case 0:
info.type = PropertyInfo.INTEGER_CLASS;
info.name = "TableID";
break;
case 1:
info.type = PropertyInfo.INTEGER_CLASS;
info.name = "Capacity";
break;
case 2:
info.type = PropertyInfo.STRING_CLASS;
info.name = "StatusFlag";
break;
case 3:
info.type = PropertyInfo.INTEGER_CLASS;
info.name = "currentWaiter";
break;
default:break;
}
}
@Override
public void setProperty(int arg0, Object value) {
switch(arg0)
{
case 0:
TableID = Integer.parseInt(value.toString());
break;
case 1:
Capacity = Integer.parseInt(value.toString());
break;
case 2:
StatusFlag = value.toString();
break;
case 3:
currentWaiter = value.toString();
break;
default :
break;
}
}
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问题在于线路
SoapObject pii = (SoapObject) soap.getProperty(i);
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它不喜欢那里的铸造.我对如何解决这个问题感到茫然.
感谢您的时间和帮助!
小智 15
而不是使用
SoapObject response = (SoapObject)envelope.getResponse();
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使用
SoapObject response = (SoapObject)envelope.bodyIn;
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这对我有用.
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