Objective-C中的@运算符与C中的&运算符相同吗？

Question

新目标C.试图理解目标C中的指针.

我的代码

#import <Foundation/Foundation.h>

 int main (int argc, const char * argv[]) {

    NSAutoreleasePool * pool = [[NSAutoreleasePool alloc] init];

NSString *msg = @"Hello Bhai";
NSLog(@" address is %i for msg", msg);
NSLog(@" which is same address  %i for Hello Bhai", @"Hello Bhai");
NSLog(@" which is different address  %i for Hello mere Bhai", @"Hello mere Bhai");
NSLog(@" value is %@ at the address for msg", msg);


[pool drain];
    return 0;
}

输出是

[Session started at 2011-04-26 16:31:11 -0400.]
2011-04-26 16:31:11.656 BasicObjC[1523:10b]  address is 8240 for msg
2011-04-26 16:31:11.658 BasicObjC[1523:10b]  which is same address  8240 for Hello Bhai
2011-04-26 16:31:11.659 BasicObjC[1523:10b]  which is different address  8288 for Hello mere Bhai
2011-04-26 16:31:11.660 BasicObjC[1523:10b]  value is Hello Bhai at the address for msg

这是否意味着Objective C中的@与C中的&相同

Answer 1

@用于表示该字符串是NSString文字,因此您可以将其分配给NSString对象.

如果你想打印一些地址,那么你应该使用%p格式说明符,而不是%i,例如

NSLog(@" address is %p for msg", msg);