Pat*_*han 7 python marshmallow
我创建一个简单的Web API,与flask和sqlalchemy与marshmallow为串行,这里是UserModel。
class UserModel(db.Model):
__tablename__ = 'users'
id = db.Column(db.Integer, primary_key = True)
username = db.Column(db.String(120), unique = True, nullable = False)
password = db.Column(db.String(120), nullable = False)
user_role = db.Column(db.String(10), nullable = False)
access_token = db.Column(db.String(120), unique = True, nullable = True, default='as' )
refresh_token = db.Column(db.String(120), unique = True, nullable = True, default='as' )
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和模式,
class UserSchema(Schema):
username = fields.Str()
password = fields.Str()
user_role = fields.Str()
access_token = fields.Str()
refresh_token = fields.Str()
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当我尝试使用 post 请求和 postman 像这样创建用户条目时
{
"username":"test1",
"password":"test1pswd",
"user_role":"admin"
}
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它在控制台上返回以下错误,
marshmallow.exceptions.ValidationError: {'_schema': ['Invalid input type.']}
我在这里做错了什么?
sna*_*erb 11
您正在尝试使用该Schema.load方法加载 json 。
>>> import json
>>> import marshmallow as mm
>>> class S(mm.Schema):
... username = mm.fields.Str()
... password = mm.fields.Str()
... user_role = mm.fields.Str()
... access_token = mm.fields.Str()
... refresh_token = mm.fields.Str()
...
>>> d = {'username': 'test1', 'password': 'test1pswd', 'user_role': 'admin'}
>>> S().load(json.dumps(d))
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "/home/kdwyer/.virtualenvs/so37/lib/python3.7/site-packages/marshmallow/schema.py", line 681, in load
data, many=many, partial=partial, unknown=unknown, postprocess=True
File "/home/kdwyer/.virtualenvs/so37/lib/python3.7/site-packages/marshmallow/schema.py", line 840, in _do_load
raise exc
marshmallow.exceptions.ValidationError: {'_schema': ['Invalid input type.']}
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你可以:
json.loads()在传递给之前调用数据Schema.load
>>> S().load(json.loads(json.dumps(d)))
{'password': 'test1pswd', 'user_role': 'admin', 'username': 'test1'}
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将 json 传递Schema.loads给自动反序列化
>>> S().loads(json.dumps(d))
{'password': 'test1pswd', 'user_role': 'admin', 'username': 'test1'}
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