在这种情况下如何使用mapM_

rns*_*nso 3 polymorphism haskell types foldable map-function

我正在尝试在不同的行上打印自相关结果的不同组成部分:

import Data.Vector as V
import Statistics.Autocorrelation
import Data.Typeable

sampleA = [1.0, 2.0, 3.0, 4.0, 1.0, 2.0, 3.0, 4]

main = do
    let res = autocorrelation $ V.fromList sampleA
    putStr "Type of result of autocorrelation test: "
    print $ typeOf res
    print res
    -- Prelude.mapM_ print res      -- not working; 
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输出为:

Type of result of autocorrelation test: ((Vector Double),(Vector Double),(Vector Double))

([1.0,2.5e-2,-0.45,-0.325,0.5,0.125,-0.15],[1.0,-1.3255000000000001,-1.4039375473415425,-1.442999810318651,-1.5311377955236107,-1.5364636906417393,-1.544097864842309],[1.0,1.0755000000000001,1.1539375473415425,1.192999810318651,1.2811377955236107,1.2864636906417393,1.294097864842309])
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但是,如果取消注释最后一行,则会出现错误:

• No instance for (Foldable ((,,) (Vector Double) (Vector Double)))
    arising from a use of ‘Prelude.mapM_’
• In a stmt of a 'do' block: Prelude.mapM_ print res
  In the expression:
    do { let res = autocorrelation $ fromList sampleA;
         putStr "Type of result of autocorrelation test: ";
         print $ typeOf res;
         print res;
         .... }
  In an equation for ‘main’:
      main
        = do { let res = ...;
               putStr "Type of result of autocorrelation test: ";
               print $ typeOf res;
               .... }
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如何将结果的所有部分打印在单独的行上?谢谢你的帮助。

Dan*_*ner 5

最简单的事情就是模式匹配。

main = do
    let (a,b,c) = autocorrelation $ V.fromList sampleA
    print a
    print b
    print c
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