当我们输入8和11时，为什么结果“ eightnine”在一起？

Question

当我使用输入8和11运行代码时，输​​出为

eightnine
odd
even
odd

我期望的结果是：

eight
nine
odd
even

为什么八行出现在同一行？循环有问题吗？

#include <stdio.h>
#include <string.h>

int main() {
int a, b;

    scanf("%d\n%d", &a, &b);

    char list[11][5]={"one","two","three","four","five","six","seven","eight","nine","even","odd"};
    int i;
    for (i=a;i<=b;i++)
    {
        printf("%s \n",(i<9?list[i-1]:list[9+i%2]));
    }

     return 0;
}

Answer 1

您需要char list[11][6]，也就是说，您需要5个字符的NUL（用于终止C样式字符串的0）空间。

虽然如此，我还是更喜欢

char* list[] ={"one","two","three","four","five","six","seven","eight","nine","even","odd"};

所有这些问题都消失了。让编译器进行计数！