如何从需要模板化的文件目录生成配置映射？

Question

我可以ConfigMap从目录中生成 ，但它们不会翻译模板指令或值。下面是Release.Namespace模板指令不在ConfigMap.

.
|____Chart.yaml
|____charts
|____.helmignore
|____templates
| |____my-scripts.yaml
|____values.yaml
|____test-files
  |____test1.txt

---
# templates/myscripts.yaml
apiVersion: v1
kind: ConfigMap
metadata:
  name: my-scripts
  namespace: {{ .Release.Namespace }}
data:
  test.txt: |-
{{ .Files.Get "test-files/test1.txt" | indent 4}}

# test-files/test1.txt
test file
{{ .Release.Namespace }}

当我在helm install . --dry-run --debug --namespace this-should-print这里跑步时，我得到的是什么，而不是我所期待的：

实际的：

---
# Source: test/templates/my-scripts.yaml
# templates/myscripts.yaml
apiVersion: v1
kind: ConfigMap
metadata:
  name: my-scripts
  namespace: test
data:
  test.txt: |-
    # test-files/test1.txt
    test file
    {{ .Release.Namespace }}

预期的：

---
# Source: test/templates/my-scripts.yaml
# templates/myscripts.yaml
apiVersion: v1
kind: ConfigMap
metadata:
  name: my-scripts
  namespace: test
data:
  test.txt: |-
    # test-files/test1.txt
    test file
    this-should-print

或者，我会对指定目录中以如下格式输出的每个文件感兴趣：

<filename>: |-
  <content>

Answer 1

我找到了一种使用 tpl 函数来做到这一点的方法：

---
# templates/myscripts.yaml
apiVersion: v1
kind: ConfigMap
metadata:
  name: my-scripts
  namespace: {{ .Release.Namespace }}
data:
  test.txt: |-
{{ tpl ( .Files.Get "test-files/test1.txt" ) . | indent 4 }}

新的输出与预期完全一致：

# templates/myscripts.yaml
apiVersion: v1
kind: ConfigMap
metadata:
  name: my-scripts
  namespace: this-should-print
data:
  test.txt: |-
    # test-files/test1.txt
    test file
    this-should-print

为了获得奖励积分，可以从目录中获取所有文件，而无需在配置映射中更新此列表：

---
# templates/myscripts.yaml
apiVersion: v1
kind: ConfigMap
metadata:
  name: my-scripts
  namespace: {{ .Release.Namespace }}
data:
{{ tpl (.Files.Glob "groovy-scripts/*").AsConfig . | indent 4 }}