Doobie可以select *
使用case类来方便且正确地传递参数,但是我看不到如何使用update
and 进行类似的工作insert
。
例如,给定这样的案例类:
case class Course(
sku: String,
title: String,
id: Id,
price: Int,
instructorid: Id,
groupid: Id,
shortdescription: String = "",
transcript: String = "",
project_home: String = "",
repository: String = "",
category: String = "",
image: String = "",
privacy: String = "",
language: String = "",
keywords: String = "",
goals: String = "",
instructionallevel: String = "",
audience: String = "",
studenttasks: String = "",
sections: String = "",
active: Boolean = true,
video: String = "",
paypal_button_id: String = "",
prerequisite_ids: String = ""
)
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我可以很好地select
记录。之所以可以使用这种不错的语法,是因为Doobie会遍历Course
case类的属性,并通过将其名称与courses
数据库记录字段匹配来为它们分配值:
def find(id: Id): Option[Course] =
sql"select * from courses where id = $id"
.query[Course]
.option
.transact(SQLSupport.xa)
.unsafeRunSync
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但是,insert
要求所有案例类属性都必须手动列出并与值匹配,这很可怕且容易出错:
/** @return saved Course with new Id */
def save(course: Course): Course = {
val insert: doobie.ConnectionIO[Course] = sql"""insert into courses (
sku,
title,
price,
instructorid,
groupid,
shortdescription,
transcript,
project_home,
repository,
category,
image,
privacy,
language,
keywords,
goals,
instructionallevel,
audience,
studenttasks,
sections,
active,
video,
paypal_button_id,
prerequisite_ids
) values (
${ course.sku },
${ course.title },
${ course.price },
${ course.instructorid },
${ course.groupid },
${ course.shortdescription },
${ course.transcript },
${ course.project_home },
${ course.repository },
${ course.category },
${ course.image },
${ course.privacy },
${ course.language },
${ course.keywords },
${ course.goals },
${ course.instructionallevel },
${ course.audience },
${ course.studenttasks },
${ course.sections },
${ course.active },
${ course.video },
${ course.paypal_button_id },
${ course.prerequisite_ids }
)"""
.update
.withUniqueGeneratedKeys("id")
val newCourse: Course = insert.transact(SQLSupport.xa).unsafeRunSync
newCourse
}
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同样update
也是可怕的:
/** @return updated Course, which should be identical to the given course */
def update(course: Course): Course = {
val update: doobie.ConnectionIO[Course] = sql"""update courses set
sku = ${ course.sku },
title = ${ course.title },
id = ${ course.id },
price = ${ course.price },
instructorid = ${ course.instructorid },
groupid = ${ course.groupid },
shortdescription = ${ course.shortdescription },
transcript = ${ course.transcript },
project_home = ${ course.project_home },
repository = ${ course.repository },
category = ${ course.category },
image = ${ course.image },
privacy = ${ course.privacy },
language = ${ course.language },
keywords = ${ course.keywords },
goals = ${ course.goals },
instructionallevel = ${ course.instructionallevel },
audience = ${ course.audience },
studenttasks = ${ course.studenttasks },
sections = ${ course.sections },
active = ${ course.active },
video = ${ course.video },
paypal_button_id = ${ course.paypal_button_id },
prerequisite_ids = ${ course.prerequisite_ids }
where id = ${ course.id }"""
.update
.withUniqueGeneratedKeys("id")
val modifiedCourse: Course = update.transact(SQLSupport.xa).unsafeRunSync
modifiedCourse
}
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有没有更好的办法?
Doobie
文档非常好,但有时您可能会发现自己处于某些文档中没有直接解释的场景中。
为了直接插入case class
对象(而不是其属性),您必须定义一个Write[A]
告诉Doobie
如何插入数据的对象。当案例类中的属性映射与数据库表中的属性映射略有不同时,可以使用此方法。
想象一下以下案例类:
case class Course (id: UUID, name: String, year: Int)
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在这种情况下,我们需要定义一个Write[Course]
for doobie,它是:
// Scala 3:
given Write[Course] = Write[(UUID, String, Int)].contramap(c => (c.id, c.name, c.year))
// Scala 2:
implicit val writer : Write[Course] = Write[(UUID, String, Int)].contramap(c => (c.id, c.name, c.year))
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现在,您可以运行您的Update
并将Doobie
知道如何映射您的列:
def insertCourse(course: Course): Update0 =
sql"""INSERT INTO courses (id, name, year) VALUES ($course)""".update
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此外,您可能需要这些导入:
import doobie.implicits.*
import doobie.implicits.javasql.*
import doobie.postgres.implicits.*
import doobie.*
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如果您的case class
属性及其类型与数据库表中指定的属性及其类型完全匹配,则无需手动指定,Writer[Course]
因为 Doobie 会自动为您派生它 [ 1 ],这应该对您有用:
case class Course (id: UUID, name: String, year: Int)
def insertCourse(course: Course): Update0 =
sql"""INSERT INTO courses (id, name, year) VALUES ($course)""".update
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感谢我的合作伙伴 YC 帮助我解决了这个问题!
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