我正在构建一个对评级数据执行一些过滤的查询.
假设我有一个简单的表ratings
,如下所示,存储来自在线评级工具的数据:
+----------------+----------------+--------+ | page_title | timestamp | rating | +----------------+----------------+--------+ | Abc | 20110417092134 | 1 | | Abc | 20110418110831 | 2 | | Def | 20110417092205 | 3 | +----------------+----------------+--------+
我需要在最新的10个评级中提取具有高频率低值的页面,并将此查询限制为在前一周产生至少20个评级的页面.这是我提出的非常长的查询:
SELECT a1.page_title, COUNT(*) AS rvol, AVG(a1.rating) AS theavg,
(
SELECT COUNT(*) FROM
(
SELECT * FROM ratings a2 WHERE a2.page_title = a1.page_title
AND DATE(timestamp) <= '2011-04-24' ORDER BY timestamp DESC LIMIT 10
)
AS latest WHERE rating >=1 AND rating <=2 ORDER BY timestamp DESC
)
AS lowest FROM ratings a1
WHERE DATE(a1.timestamp) <= "2011-04-24" AND DATE(a1.timestamp) >= "2011-04-17"
GROUP BY a1.page_title HAVING COUNT(*) > 20
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顶级查询查找在2011-04-24本周终端超过20个收视率,子查询应该与之间的值获取收视号[1,2]从每一篇文章的最新10条点评顶级查询.
MySQL抱怨子查询的WHERE子句中的a1.page_title是一个未知列,我怀疑这是因为a1在第二级查询中没有被定义为别名,而只是在顶级查询中,但我无能为力如何解决这个问题.
(编辑)的
我加入我的犯罪嫌疑人上面关于跨级引用另一个查询其作品精绝的说明,注意这里A1没有在子查询定义,但它是在直接父:
SELECT a1.page_title, COUNT(*) AS rvol, AVG(a1.rating) AS theavg,
(
SELECT COUNT(*) FROM ratings a2 WHERE DATE(timestamp) <= '2011-04-24'
AND DATE(timestamp) >= '2011-04-17' AND rating >=1
AND rating <=2 AND a2.page_title = a1.page_title
) AS lowest FROM ratings a1
WHERE DATE(a1.timestamp) <= '2011-04-17' AND DATE(a1.aa_timestamp) >= '2011-04-11'
GROUP BY a1.page_title HAVING COUNT(*) > 20
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我想你可能会考虑加入两个在线视图,它可能会让事情变得更好.
SELECT *
FROM (SELECT COUNT(*),
a2.page_title
FROM ratings a2
WHERE DATE(timestamp) <= '2011-04-24'
AND DATE(timestamp) >= '2011-04-17'
AND rating >= 1
AND rating <= 2
GROUP BY a2.page_title) current
JOIN
(SELECT a1.page_title,
COUNT(*) AS rvol,
AVG(a1.rating) AS theavg
FROM ratings a1
WHERE DATE(a1.timestamp) <= '2011-04-17'
AND DATE(a1.a_timestamp) >= '2011-04-11'
GROUP BY a1.page_title
HAVING COUNT(*) > 20) morethan20
ON current .page_title = morethan20.page_title
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