Cur*_*dos 1 python django django-orm
我的模特
class User(models.Model):
name = models.CharField(max_length=50)
surname = models.CharField(max_length=50)
class Phone(models.Model):
user = models.ForeignKey(Osoba, editable=False, related_name='phone', on_delete=models.CASCADE)
phone = models.CharField(max_length=50)
class Email(models.Model):
user = models.ForeignKey(Osoba, editable=False, related_name='email', on_delete=models.CASCADE)
email = models.EmailField()
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我希望只有在他的字段中没有值时才可以删除该对象
def delete_user(request, id):
user = User.objects.get(id=id)
if not user.email or user.phone:
if request.method == 'POST':
user.delete()
print(user.email)
return redirect('list_users')
return render(request,'index-delete.html', {'user': user})
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我试过了但是没用
条件为not user.email.exists() and not user.phone,因为的not优先级高于and和or:
def delete_user(request, id):
user = User.objects.get(id=id)
if request.method == 'POST':
if not user.email.exists() and not user.phone.exists():
user.delete()
return redirect('list_users')
return render(request,'index-delete.html', {'user': user})Run Code Online (Sandbox Code Playgroud)
所以这里的user,如果将被删除两者的email和phone为空白(具有感实性False)。
我们可以通过在数据库中搜索来提高效率:
def delete_user(request, id):
if request.method == 'POST':
done, __ = user.objects.filter(id=id, email=None, phone=None).delete()
if done:
return redirect('list_users')
user = User.objects.get(id=id)
return render(request,'index-delete.html', {'user': user})Run Code Online (Sandbox Code Playgroud)
因此,这里我们在数据库上执行JOIN,以一个查询知道用户是否没有电子邮件和电话。