将嵌套字典转换为元组列表

Question

我有一个dictionary-

d={'revenues':
             {
              '201907':
                      {'aaa.csv':'fdwe34x2'},
              '201906':{'ddd.csv':'e4c5q'}
             },    
   'complaints':
             {'2014':
                    {'sfdwa.csv','c2c2jh'}
             }
  }

我想把它转换list成tuples-

[
 ('revenues','201907','aaa.csv','fdwe34x2'),
 ('revenues','201906','ddd.csv','e4c5q'),
 ('complaints','2014','sfdwa.csv','c2c2jh')
]

我尝试使用list comprehensions，但没有帮助 -

l = [(k,[(p,q) for p,q in v.items()]) for k,v in d.items()]
print(l)
    [('revenues', [('201907', {'aaa.csv': 'fdwe34x2'}), ('201906', {'ddd.csv': 'e4c5q'})]),
     ('complaints', [('2014', {'c2c2jh', 'sfdwa.csv'})])]

有什么建议么？

Answer 1

如果您不确定这个列表可能有多少层，那么似乎您需要的是递归：

def unnest(d, keys=[]):
    result = []
    for k, v in d.items():
        if isinstance(v, dict):
            result.extend(unnest(v, keys + [k]))
        else:
            result.append(tuple(keys + [k, v]))
    return result

友情提醒：在 Python 3.6 之前，不维护 dict 顺序。

[('complaints', '2014', 'sfdwa.csv', 'c2c2jh'),
 ('revenues', '201906', 'ddd.csv', 'e4c5q'),
 ('revenues', '201907', 'aaa.csv', 'fdwe34x2')]