如何使用winrun4j创建Windows服务

Question

我一直在阅读文档,但我无法启动和停止服务.

我的.ini文件是:

main.class=test.TestService
service.class=test.TestService
service.id=StreamServer
service.name=StreamServer
service.description=Servidor que proporciona una comunicación con streams.
service.controls=stop   
classpath.1=*.jar

TestService类是:

package test;

public class TestService{
    private static TestServer server;

    public static void main (String[] args){
        if (args.length == 1){
            if (args[0].equals ("start")){
                if (server == null){
                    server = new TestServer (5000);
                    server.start ();
                }
            }else if (args[0].equals ("stop")){
                if (server != null){
                    server.stop ();
                    server = null;
                }
            }
        }
    }
}

我必须修改这个类,但我不知道如何.

谢谢.

Answer 1

从winrun4j网站的首页看一下示例服务:

package org.boris.winrun4j.test;

import org.boris.winrun4j.AbstractService;
import org.boris.winrun4j.EventLog;
import org.boris.winrun4j.ServiceException;

/**
 * A basic service.
 */
public class ServiceTest extends AbstractService
{
    public int serviceMain(String[] args) throws ServiceException {
        int count = 0;
        while (!shutdown) {
            try {
                Thread.sleep(6000);
            } catch (InterruptedException e) {
            }

            if (++count % 10 == 0)
                EventLog.report("WinRun4J Test Service", EventLog.INFORMATION, "Ping");
        }

        return 0;
    }
}

启动服务时将调用serviceMain方法.在服务准备好关闭之前,您不应该从此方法返回.还要检查"shutdown"标志 - 当您在服务控制面板中单击"停止"(或需要停止服务时)时,此标志将设置为true.