联系人选择器,检索姓氏,名字,电话号码

Question

现在,我可以检索电话号码并将editText的文本设置为该号码.但是,当我尝试获取姓氏或名字时,它不起作用.请注意我评论的内容.

继承我的代码:

import android.app.Activity;
import android.content.Intent;
import android.database.Cursor;
import android.net.Uri;
import android.os.Bundle;
import android.provider.ContactsContract;
import android.provider.ContactsContract.CommonDataKinds.Phone;
import android.view.View;
import android.widget.Button;
import android.widget.EditText;

public class main extends Activity {

    private static final int CONTACT_PICKER_RESULT = 1001; 
    /** Called when the activity is first created. */
    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.main);
        Button getContacts = (Button)findViewById(R.id.getContacts);
        getContacts.setOnClickListener(new View.OnClickListener() {

            @Override
            public void onClick(View v) {
                Intent i = new Intent(Intent.ACTION_PICK,
                        ContactsContract.CommonDataKinds.Phone.CONTENT_URI);
                startActivityForResult(i, CONTACT_PICKER_RESULT);

            }
        });
    }
    protected void onActivityResult(int reqCode, int resultCode, Intent data) {
        super.onActivityResult(reqCode, resultCode, data);
        if(resultCode == RESULT_OK) {
            switch (reqCode) {
            case CONTACT_PICKER_RESULT:
                Cursor cursor = null;
                String number = "";
                String lastName ="";
                try {

                    Uri result = data.getData();

                    //get the id from the uri
                    String id = result.getLastPathSegment();  

                    //query
                    cursor = getContentResolver().query(
                            ContactsContract.CommonDataKinds.Phone.CONTENT_URI,
                            null,
                            ContactsContract.CommonDataKinds.Phone._ID + " = ? " , new String[] {id}, null);

//                  cursor = getContentResolver().query(Phone.CONTENT_URI,
//                          null, Phone.CONTACT_ID + "=?", new String[] { id },
//                          null);

                    int numberIdx = cursor.getColumnIndex(Phone.DATA);  

                    if(cursor.moveToFirst()) {
                        number = cursor.getString(numberIdx);
                        //lastName = cursor.getString(cursor.getColumnIndex(ContactsContract.CommonDataKinds.StructuredName.FAMILY_NAME));
                    } else {
                        //WE FAILED
                    }
                } catch (Exception e) {
                    //failed
                } finally {
                    if (cursor!=null) {
                        cursor.close();
                    }
                    EditText numberEditText = (EditText)findViewById(R.id.number);
                    numberEditText.setText(number);
                    //EditText lastNameEditText = (EditText)findViewById(R.id.last_name);
                    //lastNameEditText.setText(lastName);

                }

            }
        }

Answer 1

这就是我得到显示名称的方式......

@Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) {
    if (resultCode == RESULT_OK) {
        switch (requestCode) {
        case CONTACT_PICKER_RESULT:
            Cursor cursor = null;

            try {
                Uri result = data.getData();
                String id = result.getLastPathSegment();

                //Get Name
                cursor = getContentResolver().query(result, null, null, null, null);
                if (cursor.moveToFirst()) {
                    name = cursor.getString(cursor.getColumnIndex(ContactsContract.Contacts.DISPLAY_NAME));
                } catch (Exception e) { }
        }
    }
}

希望能帮助到你 :)