更新功能以识别链接

Question

我有此功能来识别和转换标签，表情符号等

function convert_text($str) {
        $regex = "/[@#](\w+)/";
    //type and links
        $hrefs = [
            '#' => 'hashtag.php?hashtag',
            '@' => 'user.php?user'
        ];

        $result = preg_replace_callback($regex, function($matches) use ($hrefs) {
             return sprintf(
                 '<a href="%s=%s">%s</a>',
                 $hrefs[$matches[0][0]],
                 $matches[1], 
                 $matches[0]
             );
        }, $str);

        //$result = preg_replace("/U\+([A-F0-9]{5})/", '\u{${1}}', $result);
        $result = preg_replace('/U\+([A-F0-9]{5})/', '<span style="font-size:30px;">&#x\\1;</span>', $result);

        return ($result);
    }

我想，使其认识http://并https://从文字和比转换为：

<a href="http://link.com">http://link.com</a> 如何在函数内部实现呢？

Answer 1

我的猜测是，也许您可​​能想写一些接近的表达式，

\bhttps?:\/\/\S*\b

演示版

比赛

$re = '/\bhttps?:\/\/\S*\b/s';
$str = 'some text before http://some_domain.com/some_link some text before  https://www.some_domain.com/some_link some text after';

preg_match_all($re, $str, $matches, PREG_SET_ORDER, 0);

var_dump($matches);

输出量

array(2) {
  [0]=>
  array(1) {
    [0]=>
    string(32) "http://some_domain.com/some_link"
  }
  [1]=>
  array(1) {
    [0]=>
    string(37) "https://www.some_domain.com/some_link"
  }
}

更换

$re = '/(\bhttps?:\/\/\S*\b)/s';
$str = 'some text before http://some_domain.com/some_link some text before  https://www.some_domain.com/some_link some text after';
$subst = '<a href="$1">$1</a>';

echo preg_replace($re, $subst, $str);

输出量

some text before <a href="http://some_domain.com/some_link">http://some_domain.com/some_link</a> some text before  <a href="https://www.some_domain.com/some_link">https://www.some_domain.com/some_link</a> some text after

如果您想探索/简化/修改该表达式，请在regex101.com的右上方面板中进行 说明。如果愿意，您还可以在此链接中观看，它将如何与某些示例输入匹配。

RegEx电路

jex.im可视化正则表达式：