我有以下用例:
    User Object is as followed:
    UserId      payload
    123         abc1
    123         abc2
    456         pqr1
    456         pqr2
    678         xyz1
And after iterating above list<User Object>, Result should be like: 
{123=[abc1, abc2], 456=[pqr1,pqr2], 678=[xyz1]}
这样我就可以使用键(123)的值(其他对象的列表)进行进一步处理。最好的方法是什么?
我在下面尝试过,但不确定如果对象大小增加,性能效率如何。
Map<String,List<String>> userMap = new HashMap<String, List<String>>();     
for(User user: users) {
  String userId = user.getUserId();
  List<String> payloads = new ArrayList<String>();
  if(userMap.containsKey(userId)) {
      payload = userMap.get(userId);
                  payloads.add(user.getPayload());
      userMap.put(userId, payloads);
  }
  else {
      payloads.add(user.getPayload());
      userMap.put(user.getUserId(), payloads);
  }
 }
最简单的方法是stream使用Listand Collectors#groupingBy:Collectors#mapping
Map<String, List<String>> userMap = users.stream()
    .collect(Collectors.groupingBy(User::getUserId, 
        Collectors.mapping(User::getPayload, Collectors.toList())));
输出:
{123=[abc1, abc2], 456=[pqr1, pqr2], 678=[xyz1]}