用空值过滤掉数组中的obj

Question

我想过滤掉我的具有null或""值的对象数组中的对象。

let data = [{
  "name": "Product 2",
  "link": "/stock/product2",
  "category": "234",
  "description": ""
}, {
  "name": "Product 1",
  "link": "/stock/product1",
  "category": "1231",
  "description": ""
}, {
  "name": "",
  "link": null,
  "ticker": "",
  "description": ""
}]

data = data.filter(cv => (cv.name === "" && cv.link === null));

console.log(JSON.stringify(data))

如您在上面所看到的，我目前得到了假对象。我想回来：

{
  "name": "Product 2",
  "link": "/stock/product2",
  "category": "234",
  "description": ""
}, {
  "name": "Product 1",
  "link": "/stock/product1",
  "category": "1231",
  "description": ""
}

有什么建议我做错了吗？

Answer 1

因为filter按照您的想法无法正常工作，所以它保留了满足条件的元素，因此反转条件，它应该可以按预期工作：

let data = [{
  "name": "Product 2",
  "link": "/stock/product2",
  "category": "234",
  "description": ""
}, {
  "name": "Product 1",
  "link": "/stock/product1",
  "category": "1231",
  "description": ""
}, {
  "name": "",
  "link": null,
  "ticker": "",
  "description": ""
}]

data = data.filter(cv => !(cv.name === "" || cv.link === null));

console.log(JSON.stringify(data))