如何仅将字符串列表的一部分转换为整数

Question

我有一个列表列表，例如：

[['c', '2', '3', '4', 'd', '1'], ['e', '14', '16', '18', 'f', '1'], etc.]

它们都遵循相同的模式（一个字符串，三个数字字符串，一个字符串，一个数字字符串）。我想将所有数字字符串都转换为整数，但这样做有困难。

I have tried an exception loop, which doesn't seem to be working (I'm not sure why). I know its targeting the sublists as originally I got a value error of int() doesn't recognise base 10 'c' (the first letter in the first element of the sublist.

[['c', '2', '3', '4', 'd', '1'], ['e', '14', '16', '18', 'f', '1'], etc.]

When I print the results with the exception loop in it, it still produces a list of lists as if the exception wasn't there in the first place. e.g.

[['c', '2', '3', '4', 'd', '1'], ['e', '14', '16', '18', 'f', '1'], etc.] 

whereas I expect it to be:

[['c', 2, 3, 4, 'd', 1], ['e', 14, 16, 18, 'f', 1], etc.]

这是一个数据集分析，因此需要保留在列表格式列表中（因此，我不能仅使用rows.append来定位列表，因为它改变了分割最终数据的方式）。我在想，如果我无法解决这个问题，我可能会尝试将完整列表转换为元组，并使用字符异常循环，然后尝试将其转换并拆分回列表列表。我们将不胜感激，或者以其他方式获得此结果的任何帮助或理解，为什么该循环不起作用。

谢谢！

Answer 1

使用：

print([[int(x) if x.isdigit() else x for x in i] for i in rows])

完整代码：

rows = []
with open(path) as infile:
    for line in infile:
        line = line.strip()
        if not line:
            continue
        rows.append(line.split("\t"))
rows = [[int(x) if x.isdigit() else x for x in i] for i in rows]
del rows[0]