为什么没有填充 Formik `touched` 属性？

Question

我正在使用 React、Formik、react-bootstrap 和 yup 制作表单以进行验证。我正在尝试显示验证错误，但该touched属性未填充字段。

const schema = yup.object({
  name: yup.string().required(),
  email: yup
    .string()
    .email()
    .required(),
});

const ChildForm = props => {
  const { child: { name = '', email = '' } = {} } = props;
  const submitHandler = ({name, email}) => console.log(name, email);

  return (
    <Formik
      validationSchema={schema}
      onSubmit={submitHandler}
      initialValues={{ name, email }}
      render={({ handleSubmit, handleChange, values, touched, errors }) => 
      {
        console.log('touched: ', touched);
        return (
          <Form noValidate className="mt-4" onSubmit={handleSubmit}>
            <Form.Row>
              <Form.Group as={Col} controlId="name">
                <Form.Label>Full Name</Form.Label>
                <Form.Control
                  name="name"
                  required
                  value={values.name}
                  onChange={handleChange}
                  isValid={touched.name && !errors.name}
                  isInvalid={touched.name && errors.name}
                  type="text"
                  placeholder="Your child's name"
                />
                <Form.Control.Feedback>Looks good!</Form.Control.Feedback>
                <Form.Control.Feedback type="invalid">
                  {errors.name || 'Please enter your child\'s name'}
                </Form.Control.Feedback>
              </Form.Group>
            </Form.Row>
            <Form.Row>
              <Form.Group as={Col} controlId="email">
                <Form.Label>Email Address</Form.Label>
                <Form.Control
                  name="email"
                  required
                  value={values.email}
                  onChange={handleChange}
                  isValid={touched.email && !errors.email}
                  isInvalid={touched.email && errors.email}
                  type="text"
                  placeholder="Your child's email address"
                />
                <Form.Control.Feedback>
                  No spam, we promise!
                </Form.Control.Feedback>
                <Form.Control.Feedback type="invalid">
                  {errors.email || 'Please enter a valid email address'}
                </Form.Control.Feedback>
              </Form.Group>
            </Form.Row>
            <Form.Row className="float-right">
              <Button variant="success" onClick={handleSubmit}>
                <Icon icon={faSave} />
                &nbsp; Submit
              </Button>
            </Form.Row>
          </Form>
        );
      }}
    />
  );
}

我在这里做错了什么？将console.log(touched)始终显示一个空的对象。

Answer 1

我通过访问handleBlur传入render函数参数的函数并将其添加onBlur为每个表单元素的处理程序来使其工作。不确定是否需要这样做，因为我使用的是 react-bootstrap 表单组件，但是 react-bootstrap 文档有一个 Formik 示例，但touched对象没有更新。

(
    <Formik
      validationSchema={schema}
      onSubmit={submitForm}
      initialValues={{ name, email }}
      render={({
        handleSubmit,
        handleChange,
        handleBlur, // handler for onBlur event of form elements
        values,
        touched,
        errors,
      }) => {
        return (
          <Form noValidate className="mt-4" onSubmit={handleSubmit}>
            <Form.Row>
              <Form.Group as={Col} controlId="nameControl">
                <Form.Label>Full Name</Form.Label>
                <Form.Control
                  name="name"
                  required
                  value={values.name}
                  onChange={handleChange}
                  onBlur={handleBlur} // This apparently updates `touched`?
                  isValid={touched.name && !errors.name}
                  isInvalid={touched.name && errors.name}
                  type="text"
                  placeholder="Your child's name"
                />
                <Form.Control.Feedback>Looks good!</Form.Control.Feedback>
                <Form.Control.Feedback type="invalid">
                  {errors.name || 'Please enter your child\'s name'}
                </Form.Control.Feedback>
              </Form.Group>
            </Form.Row>

Answer 2

@djheru 您的解决方案是正确的，因为 Formiktouched在blurevent 而不是 on 上设置标志change。这是 Formik 作者对此的评论：您必须调用 FormikshandleBlur来通知 Formikblur事件已被触发 - 所以是的，需要这些处理程序。