T.T*_*.T. 2 windows math integer batch-file
echo The error level is: %ERRORLEVEL%
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产生
>The error level is: 15
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我想要的是什么:
>The error level is: F
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我是否需要进行转换,还是有办法以不同的方式显示数字?
感谢您对正确方向的任何帮助表示赞赏.
很久以前,我很无聊.
cmdcalc.cmd
@echo off
if not defined trace set trace=rem
%trace% on
SetLocal
if "%1"=="/?" (
call :help %0
goto :eof
)
Set MinInBase=
if /i "%2" EQU "Bin" call :DoBin %1
if /i "%2" EQU "Hex" call :DoHex %1
If not defined BinStr call :DoDec %1
EndLocal & set RET=%RET%
goto :eof
:DoBin
Set MinInBase=2
Set ShiftBy=1
Set StartSyn=0b
call :DoCalc %1
goto :eof
:DoHex
Set MinInBase=16
Set ShiftBy=4
Set StartSyn=0x
call :DoCalc %1
goto :eof
:DoDec
if {%1} EQU {} goto :eof
set /a BinStr=%1
set RET=%BinStr%
echo %RET%
goto :eof
:DoCalc
Set BinStr=
SET /A A=%1
%Trace% %A%
:StartSplit
SET /A B="A>>%ShiftBy%"
%Trace% %B%
SET /A C="B<<%ShiftBy%"
%Trace% %C%
SET /A C=A-C
%Trace% %C%
call :StringIt %C%
If %B% LSS %MinInBase% goto :EndSplit
set A=%B%
goto :StartSplit
:EndSplit
call :StringIt %B%
set RET=%StartSyn%%BinStr%
Echo %RET%
EndLocal & set RET=%RET%
goto :eof
:StringIt
set Bin=0123456789ABCDEF
FOR /F "tokens=*" %%A in ('echo "%%BIN:~%1,1%%"') do set RET=%%A
set ret=%ret:"=%
Set BinStr=%Ret%%BinStr%
goto :eof
:help
echo %1 syntax:
echo.
echo %1 Calculation [Hex^|Bin]
echo.
echo eg %1 12*2 Hex
echo.
echo gives 0x18.
goto :eof
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根据外部资源Windows Environment Variables,有一个未记录的内置只读变量=ExitCode,它以十六进制格式返回当前退出代码.要确保该ErrorLevel值等于退出代码,请使用cmd /C exit %ErrorLevel%.
所以如果你使用这个行代码...:
cmd /C exit %ErrorLevel%
echo The error level is: %=ExitCode%
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......你会收到这个(假设ErrorLevel是15):
Run Code Online (Sandbox Code Playgroud)The error level is: 0000000F
要摆脱前导零,请使用此...:
cmd /C exit %ErrorLevel%
for /F "tokens=* delims=0" %%Z in ("%=ExitCode%") do set "HEXCODE=%%Z"
if not defined HEXCODE set "HEXCODE=0"
echo The error level is: %HEXCODE%
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......得到这个:
Run Code Online (Sandbox Code Playgroud)The error level is: F