使用XSD架构进行Xml验证

Question

以下代码帮助我验证具有XSD架构的XML文件.

XmlReaderSettings settings = new XmlReaderSettings();
settings.Schemas.Add(null, xsdFilePath);
settings.ValidationType = ValidationType.Schema;
settings.ValidationEventHandler += new System.Xml.Schema.ValidationEventHandler(settings_ValidationEventHandler);
XmlDocument document = new XmlDocument();
document.Load(xmlFilePath);
XmlReader rdr = XmlReader.Create(new StringReader(document.InnerXml), settings);

while (rdr.Read())
{

}
isValid = true;

ValidationEventHandler还告诉我错误是什么,但没有告诉我他们所在的"哪里"或"在哪一行".有没有办法获得XML无法验证的行号？

Answer 1

这不是你做的事情吗？

创建一个XmlReaderSettings对象并通过该对象启用警告.

不幸的是,似乎无法将自己的XmlReaderSettings对象传递给XmlDocument.Validate().
相反,您可以使用验证XmlReader和XmlNodeReader验证现有XmlDocument(使用XmlNodeReaderwith StringReader而不是an XmlDocument)

XmlDocument x = new XmlDocument();
x.LoadXml(XmlSource);

XmlReaderSettings settings = new XmlReaderSettings();
settings.CloseInput = true;     
settings.ValidationEventHandler += Handler;

settings.ValidationType = ValidationType.Schema;
settings.Schemas.Add(null, ExtendedTreeViewSchema);
settings.ValidationFlags =
     XmlSchemaValidationFlags.ReportValidationWarnings |
XmlSchemaValidationFlags.ProcessIdentityConstraints |
XmlSchemaValidationFlags.ProcessInlineSchema |
XmlSchemaValidationFlags.ProcessSchemaLocation ;

StringReader r = new StringReader(XmlSource);

using (XmlReader validatingReader = XmlReader.Create(r, settings)) {
        while (validatingReader.Read()) { /* just loop through document */ }
}

和处理程序:

private static void Handler(object sender, ValidationEventArgs e)
{
        if (e.Severity == XmlSeverityType.Error || e.Severity == XmlSeverityType.Warning)
          System.Diagnostics.Trace.WriteLine(
            String.Format("Line: {0}, Position: {1} \"{2}\"",
                e.Exception.LineNumber, e.Exception.LinePosition, e.Exception.Message));
}