new*_*per 6 react-native react-native-maps
我在android上使用react-native-maps。我放置了一个自定义按钮,单击该按钮应转到提供的坐标(我当前的位置)
<MapView
ref={(map) => { this.map = map; }}
provider={PROVIDER_GOOGLE}
style={{ height: '100%', width: '100%' }}
annotations={markers}
showsUserLocation={true}
showsMyLocationButton={true}
initialRegion={this.state.region}
onRegionChangeComplete={this.onRegionChange}
>
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我的按钮 -
<TouchableOpacity onPress={this.gotToMyLocation} style={[Style.alignJustifyCenter, {
width: 60, height: 60,
position: "absolute", bottom: 20, right: 20, borderRadius: 30, backgroundColor: "#d2d2d2"
}]}>
<Image
style={{ width: 40, height: 40 }}
source={Images.myLocation}
/>
</TouchableOpacity>
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获取到我的位置方法 -
gotToMyLocation(){
console.log('gotToMyLocation is called')
navigator.geolocation.getCurrentPosition(
({ coords }) => {
console.log("curent location: ", coords)
console.log(this.map);
if (this.map) {
console.log("curent location: ", coords)
this.map.animateToRegion({
latitude: coords.latitude,
longitude: coords.longitude,
latitudeDelta: 0.005,
longitudeDelta: 0.005
})
}
},
(error) => alert('Error: Are location services on?'),
{ enableHighAccuracy: true }
)
}
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console.log(this.map) 始终显示未定义。
我想在单击按钮时将地图移动到当前位置。
my location按钮 showsUserLocation={true}
showsMyLocationButton={true}
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例子:
<MapView
provider={PROVIDER_GOOGLE}
showsUserLocation={true}
showsMyLocationButton={true}
style={{
...StyleSheet.absoluteFillObject,
width: '100%',
}}
initialRegion={{
latitude: targetLocation.latitude,
longitude: targetLocation.longitude,
latitudeDelta: 0.0922,
longitudeDelta: 0.0421,
}}>
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<MaterialIcons
style={style.myLocationIcon}
name="my-location"
onPress={() => {
dispatch(settingActions.getLocation());
mapRef.current.animateToRegion({
latitude: myLatitude,
longitude: myLongitude,
latitudeDelta: 0.0922,
longitudeDelta: 0.0421,
});
}}
/>
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为此,您需要定义mapRef
export const mapRef = React.createRef();
return(
<MapView
ref={mapRef}
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mapRef.current.animateToRegion({当您从一个位置切换到另一个位置时,它将处理动画。
实际上我发现了一个愚蠢的错误,绑定该方法可以使其工作。可能对某人有用。this.gotToMyLocation = this.gotToMyLocation.bind(this);
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