如何在python 3.6中整齐地打印一长串数字？

Question

>>> text = [ str(i) for i in range(1, 100)]
>>> print( " {}".format( ", ".join( str(i) for i in text ) ) )
1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52, 53, 54, 55, 56, 57, 58, 59, 60, 61, 62, 63, 64, 65, 66, 67, 68, 69, 70, 71, 72, 73, 74, 75, 76, 77, 78, 79, 80, 81, 82, 83, 84, 85, 86, 87, 88, 89, 90, 91, 92, 93, 94, 95, 96, 97, 98, 99

我不想打印长文本字符串，而是希望整齐地打印出text每行80个字符的宽度，每行缩进2个字符空间，并且每个元素均等间距，如下所示：

   1,  2,  3,  4,  5,  6,  7,  8,  9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 
  21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40,
  41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52, 53, 54, 55, 56, 57, 58, 59, 60,
  61, 62, 63, 64, 65, 66, 67, 68, 69, 70, 71, 72, 73, 74, 75, 76, 77, 78, 79, 80,
  81, 82, 83, 84, 85, 86, 87, 88, 89, 90, 91, 92, 93, 94, 95, 96, 97, 98, 99

是否有现成的python对象可用于执行此操作？如果没有，在python 3.6中实现此目标的pythonic方式是什么？

Answer 1

正如Saelyth所指出的那样，使用textwrap来格式化该格式，但是在此之前，您需要正确格式化每个数字并占用2个空格：

import textwrap

text = [str(i) for i in range(1, 100)]
one_line = ', '.join('{:>2}'.format(e) for e in text)
# one_line == ' 1,  2,  3, ...'
print('\n'.join(textwrap.wrap(one_line, width=80)))

输出：

 1,  2,  3,  4,  5,  6,  7,  8,  9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20,
21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40,
41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52, 53, 54, 55, 56, 57, 58, 59, 60,
61, 62, 63, 64, 65, 66, 67, 68, 69, 70, 71, 72, 73, 74, 75, 76, 77, 78, 79, 80,
81, 82, 83, 84, 85, 86, 87, 88, 89, 90, 91, 92, 93, 94, 95, 96, 97, 98, 99

更新资料

如果要2位缩进，则第一种方法是使用缩进来打印每行：

import textwrap

text = [str(i) for i in range(1, 100)]
one_line = ', '.join('{:>2}'.format(e) for e in text)
# one_line == ' 1,  2,  3, ...'
for line in textwrap.wrap(one_line, width=78):
    print('  {}'.format(line))

第二种方法是使用textwrap.indent：

import textwrap

text = [str(i) for i in range(1, 100)]
one_line = ', '.join('{:>2}'.format(e) for e in text)
# one_line == ' 1,  2,  3, ...'
block = '\n'.join(textwrap.wrap(one_line, width=78))
print(textwrap.indent(block, '  '))

请注意，由于缩进了2个空格，我将宽度从80减小到78。

更新2

感谢Tomerikoo的使用建议textwrap.fill，现在的代码更加简单：

import textwrap

text = [str(i) for i in range(1, 100)]
one_line = ', '.join('{:>2}'.format(e) for e in text)
# one_line == ' 1,  2,  3, ...'

print(textwrap.fill(one_line,
                    width=80,
                    initial_indent='  ',
                    subsequent_indent='  '))

更新3

在此更新中，我添加了Tim的建议以减少进一步的步骤。

import textwrap

one_line = ', '.join('{:>2}'.format(e) for e in range(1, 100))
# one_line == ' 1,  2,  3, ...'

print(textwrap.fill(one_line,
                    width=80,
                    initial_indent='  ',
                    subsequent_indent='  '))