无法定位元素：{"method":"css 选择器","selector":"#id_gender1"}

Question

我试图通过我能想到的所有可能的方式来选择一个复选框/单选按钮，但它们都不起作用。

这就是我尝试识别复选框的方式

WebElement selectGender = driver.findElement(By.id("id_gender1"));
selectGender.click();

这是 HTML 代码

<div class="radio-inline">
    <label for="id_gender1" class="top">
     <div class="radio" id="uniform-id_gender1"><span class="checked"><input type="radio" name="id_gender" id="id_gender1" value="1">
     </span>
     </div>
       Mr.
   </label>
</div>

这是我收到的错误消息。

org.openqa.selenium.NoSuchElementException: no such element: Unable to locate element: {"method":"css selector","selector":"#id_gender1"}
  (Session info: chrome=75.0.3770.142)
For documentation on this error, please visit: https://www.seleniumhq.org/exceptions/no_such_element.html
Build info: version: '3.141.59', revision: 'e82be7d358', time: '2018-11-14T08:17:03'
System info: host: 'JEFFERSONPC', ip: '192.168.100.6', os.name: 'Windows 7', os.arch: 'x86', os.version: '6.1', java.version: '1.8.0_211'
Driver info: org.openqa.selenium.chrome.ChromeDriver
Capabilities {acceptInsecureCerts: false, browserName: chrome, browserVersion: 75.0.3770.142, chrome: {chromedriverVersion: 75.0.3770.140 (2d9f97485c7b..., userDataDir: C:\Users\JEFFER~1\AppData\L...}, goog:chromeOptions: {debuggerAddress: localhost:63666}, javascriptEnabled: true, networkConnectionEnabled: false, pageLoadStrategy: normal, platform: XP, platformName: XP, proxy: Proxy(), setWindowRect: true, strictFileInteractability: false, timeouts: {implicit: 0, pageLoad: 300000, script: 30000}, unhandledPromptBehavior: dismiss and notify}
Session ID: 65163859269265511fa3118a5c9b1f79
*** Element info: {Using=id, value=id_gender1}

Answer 1

引发WebDriverWait并elementToBeClickable单击该元素。

尝试以下选项。

WebDriverWait wait = new WebDriverWait(driver, 30);
WebElement selectGender = wait.until(ExpectedConditions.elementToBeClickable(By.id("id_gender1")));
selectGender.click()

或者

WebDriverWait wait = new WebDriverWait(driver, 30);
WebElement selectGender = wait.until(ExpectedConditions.elementToBeClickable(By.xpath("//div[@class='radio-inline']/label[@for='id_gender1']")));
selectGender.click()

Answer 2

这是你的代码

  findElement(By.xpath("//input[@name='id_gender']")).click();