从时隙中删除预订的时间

Question

我想从总时隙中删除预订的时隙，我该怎么做？

输入：

实际时隙：

[ '10:00-10:30',
  '10:30-11:00',
  '11:00-11:30',
  '11:30-12:00',
  '12:00-12:30',
  '12:30-13:00',
  '13:00-13:30',
  '13:30-14:00',
  '14:00-14:30',
  '14:30-15:00',
  '15:00-15:30',
  '15:30-16:00'
]

如果预订时间段是，["11:00-13:00","14:00-15:00"]则输出应为：

[ '10:00-10:30',
   '10:30-11:00',
   '13:00-13:30',
   '13:30-14:00',
   '15:00-15:30',
   '15:30-16:00'
]

如果预订时间段是，["11:15-13:15"]则输出应为：

[ '10:00-10:30',
   '10:30-11:00',
   '13:30-14:00',
   '14:00-14:30',
   '14:30-15:00',
   '15:00-15:30',
   '15:30-16:00'
]

我已经试过了：

let actualTimeSlot = []
                            for(let i = 0; i < times_ara.length; i++) {
                                if(parseInt(times_ara[i]) < parseInt(timeBooked.split("-")[0])){
                                    actualTimeSlot.push(times_ara[i])
                                } else if(parseInt(times_ara[i]) > parseInt(timeBooked.split("-")[1])) {
                                    actualTimeSlot.push(times_ara[i])
                                } else {
                                    console.log("booked")
                                }
                            }

但不适用于所有情况

Answer 1

您可以尝试以下方法将map()时隙数组转换为对象数组：

const ts = ['10:00-10:30','10:30-11:00','11:00-11:30','11:30-12:00','12:00-12:30','12:30-13:00','13:00-13:30','13:30-14:00','14:00-14:30','14:30-15:00','15:00-15:30','15:30-16:00'];

const booked3 = ["11:00-11:30", "13:05-13:35", "14:05-14:15"];

const avail = (ts, booked) =>
	ts.map(item => {
		const[start, end] = item.split('-');
		const isBooked = booked
			.map(item => item.split('-'))
			.some(([bookedStart, bookedEnd]) =>
				(start >= bookedStart && start < bookedEnd) ||
				(end > bookedStart && end <= bookedEnd) ||
				(bookedStart >= start && bookedStart < end));
		return {slot: `${start}-${end}`, isBooked};
	})
    


console.log(avail(ts,booked3));

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