将对象转换为JAXBElement

Question

我想实现一个返回JAXBElement的方法,下面是代码

@XmlRootElement(name = "history")
@XmlAccessorType(XmlAccessType.FIELD)
public class IBHistoryInfo {

     @XmlElement(name="trade")
     private List<IBTradeInfo> mTrade;

     public void updateTradeValue(int reqId, String date, double open, double high, double low,
                                  double close, int volume, int count, double WAP, boolean hasGaps){



        IBTradeInfo info = new IBTradeInfo();
        info.setReqId(reqId);
        info.setDate(date);
        info.setOpen(open);
        info.setHigh(high);
        info.setLow(low);
        info.setClose(close);
        info.setVolume(volume);
        info.setCount(count);
        info.setWap(WAP);
        info.setHasGaps(hasGaps);
        this.setTradeInfo(info);

     }
      public void setTradeInfo(IBTradeInfo tradeinfo){
        mTrade.add(tradeinfo);
    }

       public List<IBTradeInfo> getTradeInfo(){
         if (mTrade == null) {
                mTrade = new ArrayList<IBTradeInfo>();
            }
            return this.mTrade;


    }
}

现在我不知道如何创建一个在上面的类中返回JAXBElement的方法

例如

 public JAXBElement<IBTradeInfo> getTradeXML(){

 return mTrade

}

Answer 1

以下是如何实现getTradeXML()方法:

public JAXBElement<IBTradeInfo> getTradeXML(){
    if(null == mTrade || mTrade.size() == 0) {
        return null;
    }
    IBTradeInfo tradeInfo = mTrade.get(0);
    QName qname = new QName("http://www.example.com", "trade-info");
    return new JAXBElement(qname, IBTradeInfo.class, tradeInfo);
}