How can I convert a char to a double from 0-1?

Question

I'm trying to convert an array of chars to an array of doubles with each one between 0-1, so that a would be 0 and z would be 1. Currently, I've thought of this method,

public static double[] charToDouble(char[] chars){
  double[] doubles=new double[chars.length];
  double one=1;
  double twentySix=26;
  double eachChar=one/twentySix;
  for(int i=0; i<chars.length; i++){
    int charNum=((int)input)-96;
    doubles[i]=eachChar*charNum;
  }
  return doubles;
}

but a would be converted to 1/26 instead of 0.

Answer 1

您需要通过划分25，不是26，因为有25个间隔 26页之间的信件。

您正在过度考虑自己的方法；在一个简单的循环中，您只需要一行代码：只需a从char每个字母的减去，然后将结果除以25：

for(int i = 0; i < chars.length; i++) {
    doubles[i] = (chars[i] - 'a') / 25d;
}

请注意25之后的小“ d”-使得25 a double，使结果a double。如果你不这样做，你得到的整数运算，这将使得除了每个字母z的农产品0。