如何将 *_Ctype_char 转换为 *_Ctype_uchar

Question

我用来cgo调用动态库中的函数，其签名如下所示：

int decompress(int, const uint8_t *, size_t, uint8_t *, size_t);

这是我的代码：

// #include statements here
import "C"
import (
    "unsafe"
)

func Decompress(comp_type int, data string, expected_size int) []byte {
    compressedData := C.CString(data)
    defer C.free(unsafe.Pointer(compressedData))
    compressedDataSize := C.ulong(len(data))

    decompressedData := C.malloc(C.ulong(C.sizeof_char * expected_size))
    defer C.free(unsafe.Pointer(decompressedData))
    decompressedDataSize := C.ulong(expected_size)

    ret_val := C.XpressDecompress(C.int(comp_type),
                                  (*C.uchar) (compressedData),
                                  compressedDataSize,
                                  (*C.uchar) (decompressedData),
                                  &decompressedDataSize)

    decompressed := C.GoBytes(decompressedData, C.int(decompressedDataSize))

    return decompressed
}

但是，当我尝试构建时出现此错误： cannot convert compressedData (type *_Ctype_char) to type *_Ctype_uchar

将输入字符串转换为 的最佳方法是什么const unsigned char*？

Answer 1

以下工作有效：

compressedData := unsafe.Pointer(data)

和

(*C.uchar) (compressedData)