在不使用FileUpload服务器控件的情况下在ASP.net中上载文件

Question

如何使用普通的旧版本获取ASP.net Web表单(v3.5)发布文件<input type="file" />？

我对使用ASP.net FileUpload服务器控件不感兴趣.

谢谢你的建议.

Answer 1

在你的aspx中:

<form id="form1" runat="server" enctype="multipart/form-data">
 <input type="file" id="myFile" name="myFile" />
 <asp:Button runat="server" ID="btnUpload" OnClick="btnUploadClick" Text="Upload" />
</form>

代码背后:

protected void btnUploadClick(object sender, EventArgs e)
{
    HttpPostedFile file = Request.Files["myFile"];

    //check file was submitted
    if (file != null && file.ContentLength > 0)
    {
        string fname = Path.GetFileName(file.FileName);
        file.SaveAs(Server.MapPath(Path.Combine("~/App_Data/", fname)));
    }
}

Answer 2

这是一个不依赖于任何服务器端控件的解决方案,就像OP在问题中描述的那样.

客户端HTML代码:

<form action="upload.aspx" method="post" enctype="multipart/form-data">
    <input type="file" name="UploadedFile" />
</form>

upload.aspx的Page_Load方法:

if(Request.Files["UploadedFile"] != null)
{
    HttpPostedFile MyFile = Request.Files["UploadedFile"];
    //Setting location to upload files
    string TargetLocation = Server.MapPath("~/Files/");
    try
    {
        if (MyFile.ContentLength > 0)
        {
            //Determining file name. You can format it as you wish.
            string FileName = MyFile.FileName;
            //Determining file size.
            int FileSize = MyFile.ContentLength;
            //Creating a byte array corresponding to file size.
            byte[] FileByteArray = new byte[FileSize];
            //Posted file is being pushed into byte array.
            MyFile.InputStream.Read(FileByteArray, 0, FileSize);
            //Uploading properly formatted file to server.
            MyFile.SaveAs(TargetLocation + FileName);
        }
    }
    catch(Exception BlueScreen)
    {
        //Handle errors
    }
}

Answer 3

你必须设置enctype的属性form来multipart/form-data; 然后您可以使用该HttpRequest.Files集合访问上传​​的文件.

Answer 4

将HTML控件与runat服务器属性一起使用

 <input id="FileInput" runat="server" type="file" />

然后在asp.net Codebehind中

 FileInput.PostedFile.SaveAs("DestinationPath");

如果您有兴趣,还有一些第三方选项可以显示进度

Answer 5

是的,你可以通过ajax post方法实现这个目标.在服务器端,您可以使用httphandler.所以我们没有按照您的要求使用任何服务器控件.

使用ajax,您还可以显示上传进度.

您必须将文件作为输入流读取.

using (FileStream fs = File.Create("D:\\_Workarea\\" + fileName))
    {
        Byte[] buffer = new Byte[32 * 1024];
        int read = context.Request.GetBufferlessInputStream().Read(buffer, 0, buffer.Length);
        while (read > 0)
        {
            fs.Write(buffer, 0, read);
            read = context.Request.GetBufferlessInputStream().Read(buffer, 0, buffer.Length);
        }
    } 

示例代码

function sendFile(file) {              
        debugger;
        $.ajax({
            url: 'handler/FileUploader.ashx?FileName=' + file.name, //server script to process data
            type: 'POST',
            xhr: function () {
                myXhr = $.ajaxSettings.xhr();
                if (myXhr.upload) {
                    myXhr.upload.addEventListener('progress', progressHandlingFunction, false);
                }
                return myXhr;
            },
            success: function (result) {                    
                //On success if you want to perform some tasks.
            },
            data: file,
            cache: false,
            contentType: false,
            processData: false
        });
        function progressHandlingFunction(e) {
            if (e.lengthComputable) {
                var s = parseInt((e.loaded / e.total) * 100);
                $("#progress" + currFile).text(s + "%");
                $("#progbarWidth" + currFile).width(s + "%");
                if (s == 100) {
                    triggerNextFileUpload();
                }
            }
        }
    }