Diz*_*zzi 4 php rename image crop resize-image
正如标题所说..如何将图像移动/重命名为新文件夹?到目前为止我有这个并且新图像被调整大小/裁剪但它不会移动到"new /"文件夹:
$in_filename = '4csrWqu9ngv.jpg';
list($width, $height) = getimagesize($in_filename);
$offset_x = 0;
$offset_y = 0;
$new_height = $height - 65;
$new_width = $width;
$image = imagecreatefromjpeg($in_filename);
$new_image = imagecreatetruecolor($new_width, $new_height);
imagecopy($new_image, $image, 0, 0, $offset_x, $offset_y, $width, $height);
header('Content-Type: image/jpeg');
imagejpeg($new_image);
$move_new = imagejpeg($new_image);
rename($move_new, 'new/' . $move_new);
Run Code Online (Sandbox Code Playgroud)
一如既往的任何帮助表示赞赏:)
您的代码中几乎没有错误.输出imagejpeg是一个布尔值,因此您的重命名始终失败.您也从未保存调整大小的图像.您必须使用第二个参数imagejpeg并提供新图像的正确文件名.另外,确保目录new存在,否则重命名将失败.
固定代码:
$in_filename = '4csrWqu9ngv.jpg';
list($width, $height) = getimagesize($in_filename);
$offset_x = 0;
$offset_y = 0;
$new_height = $height - 65;
$new_width = $width;
$image = imagecreatefromjpeg($in_filename);
$new_image = imagecreatetruecolor($new_width, $new_height);
imagecopy($new_image, $image, 0, 0, $offset_x, $offset_y, $width, $height);
/* Uncomment in case you want it also outputted
header('Content-Type: image/jpeg');
imagejpeg($new_image);
*/
imagejpeg($new_image, $in_filename);
rename($in_filename, 'new/' . $in_filename);
Run Code Online (Sandbox Code Playgroud)