如何在bash中使用mod运算符？

Question

我正在尝试这样一条线:

for i in {1..600}; do wget http://example.com/search/link $i % 5; done;

我想要输出的是:

wget http://example.com/search/link0
wget http://example.com/search/link1
wget http://example.com/search/link2
wget http://example.com/search/link3
wget http://example.com/search/link4
wget http://example.com/search/link0

但我实际得到的只是:

    wget http://example.com/search/link

Answer 1

请尝试以下方法:

 for i in {1..600}; do echo wget http://example.com/search/link$(($i % 5)); done

该$(( ))语法做一个算术评估的内容.

Answer 2

for i in {1..600}
do
    n=$(($i%5))
    wget http://example.com/search/link$n
done

Answer 3

你必须将你的数学表达式放在$(())中.

一内胆:

for i in {1..600}; do wget http://example.com/search/link$(($i % 5)); done;

多行:

for i in {1..600}; do
    wget http://example.com/search/link$(($i % 5))
done

Answer 4

这可能是偏离主题的.但对于for循环中的wget,你当然可以

curl -O http://example.com/search/link[1-600]