Akz*_*kza 2 java spring entity dto spring-boot
我已经完成了获取所有数据并将对象转换为 objectDto。但是,不知何故,我觉得我的代码还不够好。在这里我需要你的帮助,我需要任何参考/建议来使我的代码更好(在性能方面)。这是我的工作代码:
@Override
public List<BookDto> findAll() throws Exception {
try {
List<Book> list = bookDao.findAll();
List<BookDto> listDto = new ArrayList<>();
for (Book book : list) {
BookDto bookDto = new BookDto();
Set<AuthorDto> listAuthorDto = new HashSet<AuthorDto>();
Set<Author> dataAuthor = new HashSet<Author>();
book.getAuthor().iterator().forEachRemaining(dataAuthor::add);
BeanUtils.copyProperties(book, bookDto, "author", "category");
bookDto.setCategory(book.getCategory().getCategory());
for (Author author : dataAuthor) {
AuthorDto authorDto = new AuthorDto();
BeanUtils.copyProperties(author, authorDto);
listAuthorDto.add(authorDto);
}
bookDto.setAuthor(listAuthorDto);
listDto.add(bookDto);
}
return listDto;
} catch (Exception e) {
throw new Exception(e);
}
}
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这是我需要的输出(已经用上面的代码实现了):
[
{
"title": "book1",
"year": "2013",
"author": [
{
"name": "john",
"address": "NY"
},
{
"name": "angel",
"address": "LA"
}
],
"category": "science"
},
{
"title": "book2",
"year": "2014",
"author": [
{
"name": "john",
"address": "NY"
}
],
"category": "science"
},
{
"title": "book3",
"year": "2009",
"author": [
{
"name": "angel",
"address": "LA"
}
],
"category": "comedy"
}
]
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与其重新发明轮子并自己编写它,不如使用为此而设计的现有库/工具。
我建议使用ModelMapper,这是一个很好的 DTO/实体映射库,您只需要一行代码即可将您的实体转换为 DTO,例如:
ModelMapper modelMapper = new ModelMapper();
BookDto bookDTO = modelMapper.map(book, BookDto.class);
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您可以查看库的示例页面或Spring REST API教程的实体到 DTO 转换以更深入地了解该库。
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