C++中结构内的向量

Question

struct node {
  char name_;
  vector<node*> nbs_;
};

node a, b, c;
  a.name_ = 'a';
  b.name_ = 'b';
  c.name_ = 'c';
  a.nbs_.push_back(&b);
  a.nbs_.push_back(&c);

  for (vector<node*>::iterator i = a.nbs_.begin(); i != a.nbs_.begin(); i++) {
    cout << (*i)->name_;
  }

为什么上面的代码不起作用.它什么都不打印.我想要它打印节点b和c的名字.

Answer 1

i != a.nbs_.begin();

应该

i != a.nbs_.end();