在 SwiftUI 中点击 ActionSheet.Button 后如何呈现视图？

Question

我一直在玩 SwiftUI 并被这个简单的事情难住了。基本上，我试图在点击ActionSheet.Button. 到目前为止，这是我的代码：

struct SomePage: View {
    @State var showSheet = false

    var body: some View {
        Button(action: {
            self.showSheet = true
        }) { 
            Text("Show ation sheet") 
        }.presentation(sheet)
    }

    private var sheet: ActionSheet? {
        let button = ActionSheet.Button.default(Text("Button") {
             self.showSheet = false
             // what now??
        }
        let action = ActionSheet(title: Text("Title"),
                                 message: nil,
                                 buttons: [button])
        return showSheet ? action : nil
    }

    // This is the modal I'm trying to present 
    // after tapping on the action sheet button
    private var modal: Modal {
        return Modal(SomePage())
    }
}

我已经尝试向presentation按钮添加第二个处理程序并切换一个showModal属性，但显然调试器抱怨在第一个仍然呈现时尝试第二个模式演示。

有没有人知道如何使这项工作？

Answer 1

你离它不远了。

添加另一个@State来处理模态的呈现。

struct ContentView: View {

    @State var showSheet = false
    @State var showModal = false

    var body: some View {
        Button(action: {
            self.showSheet = true
        }) {
            Text("Show action sheet")
        }
        .actionSheet(isPresented: $showSheet, content: actionSheet)
        .sheet(isPresented: $showModal, content: { Text("Modal") })
    }

    private func actionSheet() -> ActionSheet {
        let button = ActionSheet.Button.default(Text("Show modal")) {
            self.showSheet = false
            self.showModal = true
        }
        let actionSheet = ActionSheet(title: Text("Action Sheet"),
                                      message: nil,
                                      buttons: [button])
        return actionSheet
    }

}

结果：

为 Xcode 11 beta 5 更新