Mar*_*her 4 monads haskell monad-transformers reader-monad
我试图将ReaderT X IOmonad 视为 IO 以实现以下目标:
-- this is the monad I defined:
type Game = ReaderT State IO
runGame :: State -> Game a -> IO a
runGame state a = runReaderT a state
readState :: Game State
readState = ask
-- some IO action, i.e. scheduling, looping, etc.
ioAction :: IO a -> IO ()
ioAction = undefined
-- this works as expected, but is rather ugly
doStuffInGameMonad :: Game a -> Game ()
doStuffInGameMonad gameAction = do
state <- readState
liftIO $ ioAction $ runGame state gameAction
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ioAction例如,按时间间隔调度另一个 IO 操作。Game每次都打开monad 似乎有点麻烦——而且感觉不对。
我试图实现的是:
doStuffInGameMonad :: Game a -> Game ()
doStuffInGameMonad gameAction = ioAction $ gameAction
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我的直觉告诉我,这应该是可能的,因为我的Gamemonad 知道 IO。有没有办法隐式转换/解除Gamemonad?
如果我的术语不正确,请原谅。
您可以使用的一种抽象是包中的MonadUnliftIO类unliftio-core。您可以使用withRunInIO.
import Control.Monad.IO.Unlift (MonadUnliftIO(..))
doStuffInGameMonad :: MonadUnliftIO m => m a -> m ()
doStuffInGameMonad gameAction = withRunInIO (\run -> ioAction (run gameAction))
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另一个较少多态的解决方案是使用mapReaderT.
doStuffInGameMonad :: Game a -> Game ()
doStuffInGameMonad gameAction = mapReaderT ioAction gameAction
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