LDAP:如何获取Active Directory中的所有组?

use*_*389 9 java ldap active-directory

有没有办法使用java获取Active Directory中所有组的名称?

kal*_*yan 10

使用Java JNDI,搜索(objectclass = group)并请求cn属性.这将获得所有组名称.

代码示例:

import java.util.Hashtable;

import javax.naming.Context;
import javax.naming.NamingEnumeration;
import javax.naming.NamingException;
import javax.naming.directory.Attributes;
import javax.naming.directory.DirContext;
import javax.naming.directory.InitialDirContext;
import javax.naming.directory.SearchControls;
import javax.naming.directory.SearchResult;

public class Test {

    public static String ldapUri = "ldap://localhost";
    public static String usersContainer = "cn=users,dc=example,dc=com";

    public static void main(String args[]) {

        if (args.length != 2) {
            System.out.println("Usage: test userName password");
            return;
        }
        String username = args[0];
        String password = args[1];

        Hashtable env = new Hashtable();
        env.put(Context.INITIAL_CONTEXT_FACTORY, "com.sun.jndi.ldap.LdapCtxFactory");
        env.put(Context.PROVIDER_URL, ldapUri);
        env.put(Context.SECURITY_PRINCIPAL, username);
        env.put(Context.SECURITY_CREDENTIALS, password);
        try {
            DirContext ctx = new InitialDirContext(env);
            SearchControls ctls = new SearchControls();
            String[] attrIDs = { "cn" };
            ctls.setReturningAttributes(attrIDs);
            ctls.setSearchScope(SearchControls.ONELEVEL_SCOPE);

            NamingEnumeration answer = ctx.search(usersContainer, "(objectclass=group)", ctls);
            while (answer.hasMore()) {
                SearchResult rslt = (SearchResult) answer.next();
                Attributes attrs = rslt.getAttributes();
                System.out.println(attrs.get("cn"));
            }

            ctx.close();

        } catch (NamingException e) {
            e.printStackTrace();
        }

    }
}
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