创建一个跨浏览器的mixin进行转换:旋转

Question

我想为sass创建一个mixin,它将旋转应用于指定的元素.mixin应该采用一个参数,表示要应用的旋转度数.

从css3please.com,我发现了一种跨浏览器的方式来实现CSS:

.box_rotate {
     -moz-transform: rotate(7.5deg);  /* FF3.5+ */
       -o-transform: rotate(7.5deg);  /* Opera 10.5 */
  -webkit-transform: rotate(7.5deg);  /* Saf3.1+, Chrome */
      -ms-transform: rotate(7.5deg);  /* IE9 */
          transform: rotate(7.5deg);  
             filter: progid:DXImageTransform.Microsoft.Matrix(/* IE6–IE9  */
                     M11=0.9914448613738104, M12=-0.13052619222005157,M21=0.13052619222005157, M22=0.9914448613738104, sizingMethod='auto expand');
               zoom: 1;
}

除了讨厌的IE矩阵表示法之外,这对于混音来说都非常容易.有没有人对使用sass,javascript或两者的组合将度数转换为IE矩阵转换的方法有任何建议？

Answer 1

你去:

上海社会科学院:

@mixin rotate( $degrees )
  -webkit-transform: rotate(#{$degrees}deg)
  -moz-transform: rotate(#{$degrees}deg)
  -ms-transform: rotate(#{$degrees}deg)
  -o-transform: rotate(#{$degrees}deg)
  transform: rotate(#{$degrees}deg)

  filter:  progid:DXImageTransform.Microsoft.Matrix(sizingMethod='auto expand', M11=#{cos($degrees)}, M12=-#{sin($degrees)}, M21=#{sin($degrees)}, M22=#{cos($degrees)})
  -ms-filter: "progid:DXImageTransform.Microsoft.Matrix(sizingMethod='auto expand', M11=#{cos($degrees)}, M12=-#{sin($degrees)}, M21=#{sin($degrees)}, M22=#{cos($degrees)})"
  zoom: 1

SCSS:

@mixin rotate( $degrees ) {
  -webkit-transform: rotate(#{$degrees}deg);
  -moz-transform: rotate(#{$degrees}deg);
  -ms-transform: rotate(#{$degrees}deg);
  -o-transform: rotate(#{$degrees}deg);
  transform: rotate(#{$degrees}deg);

  filter:  progid:DXImageTransform.Microsoft.Matrix(sizingMethod='auto expand', M11=#{cos($degrees)}, M12=-#{sin($degrees)}, M21=#{sin($degrees)}, M22=#{cos($degrees)});
  -ms-filter: "progid:DXImageTransform.Microsoft.Matrix(sizingMethod='auto expand', M11=#{cos($degrees)}, M12=-#{sin($degrees)}, M21=#{sin($degrees)}, M22=#{cos($degrees)})";
  zoom: 1;
 }

用法:

@include rotate( 24 )

或者你可以简单地使用罗盘,让你的生活更轻松:P

Answer 2

的旋转矩阵被定义为

[[cos(A), -sin(A)],
 [sin(A),  cos(A)]]

A角度在哪里.M11在IE矩阵中是第一行的第一个元素; M12:第一行的第二个元素等

JavaScripts Math.sin并Math.cos使用弧度操作,因此您必须将度数转换为弧度

radians = degrees * Math.PI / 180

把这个放在一起我们得到这个功能:

function rotationMatrix(degrees) {
  var A = degrees * Math.PI / 180;
  return [[Math.cos(A), -Math.sin(A)], [Math.sin(A),  Math.cos(A)]]
}

例:

rotationMatrix(10) 
// => [[0.984807753012208, -0.17364817766693033], 
//     [0.17364817766693033, 0.984807753012208]]

Answer 3

此函数允许将度数转换为IE矩阵变换.

//deg input defines the requested angle of rotation.
function degreeToIEMatrix(deg){   
    var deg2radians = Math.PI * 2 / 360;
    var rad = deg * deg2radians ;
    var costheta = Math.cos(rad);
    var sintheta = Math.sin(rad);

    var M11 = costheta;
    var M12 = -sintheta;
    var M21 = sintheta;
    var M22 = costheta;
}

你会在这里找到更多的信息.