San*_*ker 6 python sqlalchemy flask
class Team(db.Model):
__tablename__ = "Teams"
id = db.Column(db.Integer, primary_key=True)
flashscore_id = db.Column(db.String(255), nullable=False, unique=True)
name = db.Column(db.String(255), nullable=False)
leagues = db.relationship("League",
secondary=league_teams_table)
standings = db.relationship('Standing', backref='teams', cascade="all,delete")
fixtures = db.relationship('Fixture', backref='teams', cascade="all,delete")
related_fixtures_table = db.Table('RelatedFixtures',
db.Column('fixture_id', db.Integer, db.ForeignKey('Fixtures.id')),
db.Column('related_fixture_id', db.Integer, db.ForeignKey('Fixtures.id')))
class Fixture(db.Model):
__tablename__ = "Fixtures"
id = db.Column(db.Integer, primary_key=True)
home_id = db.Column(db.Integer, db.ForeignKey('Teams.id'),
nullable=False)
away_id = db.Column(db.Integer, db.ForeignKey('Teams.id'),
nullable=False)
home_ref = db.relationship("Teams", backref="fixture", uselist=False, foreign_keys=[home_id])
away_ref = db.relationship("Teams", backref="fixture", uselist=False, foreign_keys=[away_id])
flashscore_id = db.Column(db.String(255), nullable=False, unique=True)
total_goals = db.Column(db.Integer, nullable=False)
total_fh_goals = db.Column(db.Integer, nullable=False, default=0)
total_sh_goals = db.Column(db.Integer, nullable=False, default=0)
total_home_goals = db.Column(db.Integer, nullable=False)
total_away_goals = db.Column(db.Integer, nullable=False)
total_home_fh_goals = db.Column(db.Integer, nullable=False, default=0)
total_home_sh_goals = db.Column(db.Integer, nullable=False, default=0)
total_away_fh_goals = db.Column(db.Integer, nullable=False, default=0)
total_away_sh_goals = db.Column(db.Integer, nullable=False, default=0)
related_fixtures = db.relationship("Fixture",
secondary=related_fixtures_table)
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我编写了上面的代码,试图定义 Fixture 和 Team 之间的多种关系。当我运行应用程序并执行操作时,出现以下错误:
sqlalchemy.exc.AmbiguousForeignKeysError: Could not determine join condition between parent/child tables on relationship Team.fixtures - there are multiple foreign key paths linking the tables. Specify the 'foreign_keys' argument, providing a list of those columns which should be counted as containing a foreign key reference to the parent table.
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我尝试通过添加以下两行来解决此问题:
home_ref = db.relationship("Teams", backref="fixture", uselist=False, foreign_keys=[home_id])
away_ref = db.relationship("Teams", backref="fixture", uselist=False, foreign_keys=[away_id])
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但我仍然遇到同样的错误。谁能帮我吗?
您需要fixtures在Team类上配置关系,因为这就是错误告诉您要做的事情:。Could not determine join condition ... on relationship Team.fixtures
但是,您无法使用 ; 来修复这种情况foreign_keys。需要一个(可能是复合)外键,并且您有两个不同的外键关系。您必须创建两种单独的关系,一种用于该球队为主队的赛程,另一种用于该away关系。
如果您想Team.fixtures返回Fixture通过一个或两个外键引用团队的所有行的列表,您需要创建一个自定义primaryjoin条件,该条件Team.id与您的home_id 或列相匹配(并且您可能希望向查询away_id添加一个条件DISTINCT以避免通过两个外键连接到您的团队的装置获得重复的结果)。
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