绝对的uri:http://java.sun.com/jsp/jstl/core无法解析

Question

我选择了一个新创建的maven webapp项目,并想用它做最简单的mvc应用程序.我的环境看起来像这样:

<artifactId>spring-core</artifactId>
        <artifactId>spring-test</artifactId>
        <artifactId>spring-beans</artifactId>
        <artifactId>spring-context</artifactId>
        <artifactId>spring-aop</artifactId>
        <artifactId>spring-context-support</artifactId>
        <artifactId>spring-tx</artifactId>
        <artifactId>spring-orm</artifactId>  
        <artifactId>spring-web</artifactId>
        <artifactId>spring-webmvc</artifactId>
        <artifactId>spring-asm</artifactId>
        <artifactId>log4j</artifactId>
        <artifactId>hibernate-core</artifactId>
        <artifactId>hibernate-cglib-repack</artifactId>
        <artifactId>hsqldb</artifactId>

        <!-- particular arears-->
         <dependency>
           <groupId>taglibs</groupId>
           <artifactId>standard</artifactId>
           <scope>provided</scope>
        </dependency>
        <dependency>
           <groupId>javax.servlet</groupId>
           <artifactId>servlet-api</artifactId>
           <scope>provided</scope>
        </dependency>
        <!-- -->

       <spring.version>3.0.5.RELEASE</spring.version>
       <hibernate.version>3.6.1.Final</hibernate.version>
       <hibernate-cglig-repack.version>2.1_3</hibernate-cglig-repack.version>
       <log4j.version>1.2.14</log4j.version>
       <javax-servlet-api.version>2.5</javax-servlet-api.version>
       <hsqldb.version>1.8.0.10</hsqldb.version>
       <mysql-connector.version>5.1.6</mysql-connector.version>
       <slf4j-log4j12.version>1.5.2</slf4j-log4j12.version>
       <slf4j-api.version>1.5.8</slf4j-api.version>
       <javaassist.version>3.7.ga</javaassist.version>
       <taglibs.version>1.1.2</taglibs.version>


        <plugins>
        <plugin>
            <groupId>org.apache.maven.plugins</groupId>
            <artifactId>maven-compiler-plugin</artifactId>
            <version>2.0.2</version>
            <configuration>
                <source>1.6</source>
                <target>1.6</target>
            </configuration>
        </plugin>
        <plugin>
            <groupId>org.apache.maven.plugins</groupId>
            <artifactId>maven-war-plugin</artifactId>
            <version>2.1-beta-1</version>
            <configuration>
                <failOnMissingWebXml>false</failOnMissingWebXml>
            </configuration>
        </plugin>
    </plugins>
    <finalName>admin-webapp</finalName>
</build>
<profiles>
    <profile>
        <id>endorsed</id>
        <activation>
            <property>
                <name>sun.boot.class.path</name>
            </property>
        </activation>
        <build>
            <plugins>
                <plugin>
                    <groupId>org.apache.maven.plugins</groupId>
                    <artifactId>maven-compiler-plugin</artifactId>
                    <version>2.0.2</version>
                    <configuration>
                        <!-- javaee6 contains upgrades of APIs contained within the JDK itself.
                             As such these need to be placed on the bootclasspath, rather than classpath of the
                             compiler.
                             If you don't make use of these new updated API, you can delete the profile.
                             On non-SUN jdk, you will need to create a similar profile for your jdk, with the similar property as sun.boot.class.path in Sun's JDK.-->
                        <compilerArguments>
                            <bootclasspath>${settings.localRepository}/javax/javaee-endorsed-api/6.0/javaee-endorsed-api-6.0.jar${path.separator}${sun.boot.class.path}</bootclasspath>
                        </compilerArguments>
                    </configuration>
                    <dependencies>
                        <dependency>
                            <groupId>javax</groupId>
                            <artifactId>javaee-endorsed-api</artifactId>
                            <version>6.0</version>
                        </dependency>
                    </dependencies>
                </plugin>
            </plugins>
        </build>
    </profile>
</profiles>
<properties>
    <project.build.sourceEncoding>UTF-8</project.build.sourceEncoding>
    <netbeans.hint.deploy.server>Tomcat60</netbeans.hint.deploy.server>
    <tomcat.home>${env.CATALINA_HOME}</tomcat.home>
    <web.context>${project.artifactId}</web.context>
</properties>

我的applicationContext非常简单:

<context:component-scan base-package="com.personal.springtest.admin.webapp" />
<mvc:annotation-driven />

web.xml就这么简单:

<web-app xmlns="http://java.sun.com/xml/ns/javaee"
 xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
 xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd"
 version="3.0">
<session-config>
    <session-timeout>
        30
    </session-timeout>
</session-config>

<servlet>
    <servlet-name>iwadminservlet</servlet-name>
    <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
    <init-param>
        <param-name>contextConfigLocation</param-name>
        <param-value>/WEB-INF/project-admin-webapp-config.xml</param-value>
    </init-param>
    <load-on-startup>1</load-on-startup>
</servlet>

   <servlet-mapping>
    <servlet-name>iwadminservlet</servlet-name>
    <url-pattern>/</url-pattern>
   </servlet-mapping>
</web-app>

我的控制器是这样的:

@Controller
public class HomeController {

   @RequestMapping(value="/")
   public String Home(){
    System.out.print("THIS IS a demo mvc, i think i like it");
    // this is temporary, will use viewresolver when everything clears up
    return "/views/home.jsp";
   }

}

我的观点是:

<%@ taglib uri="http://java.sun.com/jsp/jstl/core" prefix="c" %>
<%@ page session="false" %>
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"    "http://www.w3.org/TR/html4/loose.dtd">
<html>
   <head>
      <meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
      <title>JSP Page</title>
   </head>
   <body>
      <h1>Hello World!</h1>
   </body>
</html>

我得到的错误是

org.apache.jasper.JasperException:绝对uri:http://java.sun.com/jsp/jstl/core无法在web.xml或使用此应用程序部署的jar文件中解析

问题1:我想知道是否由于我正在使用的版本,我想我已经阅读了关于tomcat中支持的版本的内容,以及使用的java ee版本.但实际上并没有从中找到修复我的版本问题.我怎样才能解决这个问题？

问题2:在此错误之前我有代码400因为我没有views/home.jsp正确指向它但我注意到当我在netbeans中运行应用程序时,它会打开带有url的浏览器:http:// localhot:8080 / while我期待http:// localhost:8080/admin-webapp / admin-webapp是我战争的名字.我认为这是一个问题,我想解决它.

Answer 1

您需要JSTL实现:

<dependency>
    <groupId>javax.servlet</groupId>
    <artifactId>jstl</artifactId>
    <version>1.2</version>
</dependency>

或者,如果您手动包含JSTL jar:

<dependency>
    <groupId>javax.servlet</groupId>
    <artifactId>jstl</artifactId>
    <version>1.2</version>
    <scope>provided</scope>
</dependency>