PHP根据给定索引的匹配值合并数组

Question

我有两个这样的数组：

数组1

Array
(
    [0] => Array
        (
            [ID] => 101
            [Code] => 1075
            [Date] => 2012-03-03 17:13:12.433
        )

    [1] => Array
        (
            [ID] => 103
            [Code] => 175
            [Date] => 2012-09-05 20:30:02.217
        )

    [2] => Array
        (
            [ID] => 109
            [Code] => 178
            [Date] => 2012-07-05 20:30:02.217
        )

)

阵列2

Array
(
    [0] => Array
        (
            [Amount] => 1234
            [ID] => 101
        )

    [1] => Array
        (
            [Amount] => 1342
            [ID] => 103
        )

    [2] => Array
        (
            [Amount] => 0
            [ID] => 0
        )

)

我使用此代码根据 ID 索引的匹配值组合它们。

      $combined = array();
           foreach ($arr as $arrs) {
                   $comb = array('ID' => $arrs['ID'], 'Code' => $arrs['Code'],'Date' => $arrs['Date'],'Amount' => '');
                   foreach ($arr4 as $arr2) {
                       if ($arr2['ID'] == $arrs['ID']) {
                           $comb['Amount'] = $arr2['Amount'];
                           break;
                       }
                       else {
                        $comb['Amount'] = $arr2['Amount'];
                       }
                   }
               $combined[] = $comb;
           }
echo print_r($combined);

这是我从这段代码中得到的期望输出：

Array
(
    [0] => Array
        (
            [ID] => 101
            [Code] => 1075
            [Date] => 2012-03-03 17:13:12.433
            [Amount] => 1234
        )

    [1] => Array
        (
            [ID] => 103
            [Code] => 175
            [Date] => 2012-09-05 20:30:02.217
            [Amount] => 1342
        )

    [2] => Array
        (
            [ID] => 109
            [Code] => 178
            [Date] => 2012-07-05 20:30:02.217
            [Amount] => 0
        )

)

我想优化代码，以便

$comb = array('ID' => $arrs['ID'], 'Code' => $arrs['Code'],'Date' => $arrs['Date'],'Amount' => ''); 

应该动态生成而不是硬编码。而不是$comb['Amount'] = $arr2['Amount'];我希望代码自动将所有其他字段添加到 ID 匹配的第一个数组中。

我如何实现这一目标？

Answer 1

除了 之外，使其完全动态的最简单的解决方案ID如下：

$arr2 = array_column($array2, "ID");

$finalArray = array();
foreach($array1 as $arr){
    $key = array_search($arr['ID'], $arr2);
    if($key ===false){
        $key = array_search(0, $arr2);
    }
    unset($array2[$key]['ID']);
    $finalArray[] =     array_merge($arr,$array2[$key]);
}

print_r($finalArray);

输出：- https://3v4l.org/1sDJs