将字符串拆分为Ruby中的字符对

Question

我有一个字符串(例如"AABBCCDDEEFF")并希望将其拆分为一个数组,每个元素包含两个字符 - ["AA","BB","CC","DD","EE","FF"] .

Answer 1

尝试String对象的扫描方法:

>> foo = "AABBCCDDEEFF"
=> "AABBCCDDEEFF"
>> foo.scan(/../)
=> ["AA", "BB", "CC", "DD", "EE", "FF"]

Answer 2

根据您的需要,这可能会更好:

>  foo = "AAABBCDEEFF"
=> "AAABBCDEEFF"
> foo.scan(/.{1,2}/)
=> ["AA", "AB", "BC", "DE", "EF", "F"]

不确定您的输入是什么样的.上面的答案将丢弃没有一对的任何字符,这个字符将用于奇数长度的字符串.