Anu*_*TBE 9 django django-rest-framework
我正在使用Django 2.2和Django REST Framework。
我必须为同一个模型序列化。
class OrderListSerializer(serializers.ModelSerializer):
plan = PlanBaseSerializer(read_only=True, many=False)
class Meta:
model = Order
fields = [
'id', 'name', 'plan', 'pricing',
'created', 'completed',
]
class OrderCreateSerializer(serializers.ModelSerializer):
plan_pricing = serializers.IntegerField(required=True, write_only=True)
class Meta:
model = Order
fields = [
'plan_pricing'
]
def create(self, validated_data):
plan_pricing_ = validated_data.pop('plan_pricing', None)
try:
plan_pricing = PlanPricing.objects.get(pk=plan_pricing_)
except PlanPricing.DoesNotExists:
raise ValidationError('Plan pricing not available')
validated_data['plan'] = plan_pricing.plan
validated_data['amount'] = plan_pricing.price
return super().create(validated_data)
Run Code Online (Sandbox Code Playgroud)
OrderListSerializerserializer 用于列出订单或订单详细信息视图,OrderCreateSerializer用于创建新的订单实例。
观点是
class CreateOrderView(generics.CreateAPIView):
serializer_class = OrderCreateSerializer
def perform_create(self, serializer):
serializer.save(user=self.request.user)
Run Code Online (Sandbox Code Playgroud)
这工作正常,因为订单对象正在按预期创建。但是返回的值不包含数据。
我想OrderListSerializer在创建订单后用于呈现保存的订单详细信息。
创建对象后如何更改序列化程序类?
此外,我必须在成功创建对象后触发信号。触发信号的最佳位置是什么?
JPG*_*JPG 18
更改CreateOrderView如下,
class CreateOrderView(generics.CreateAPIView):
serializer_class = OrderCreateSerializer
def perform_create(self, serializer):
return serializer.save(user=self.request.user)
def create(self, request, *args, **kwargs):
serializer = self.get_serializer(data=request.data)
serializer.is_valid(raise_exception=True)
instance = self.perform_create(serializer)
instance_serializer = OrderListSerializer(instance)
return Response(instance_serializer.data)Run Code Online (Sandbox Code Playgroud)
serializer.save()返回刚刚创建或更新的实例。因此,我们使用该实例传递给OrderListSerializer并返回相应的响应。