我正在尝试从第三方库调用 API。
当我想将 unique_ptr 与具有受保护析构函数的类一起使用时会出现问题。
这是例子,
#include <memory>
#include <iostream>
using namespace std;
class Parent {
public:
Parent () //Constructor
{
cout << "\n Parent constructor called\n" << endl;
}
protected:
~ Parent() //Dtor
{
cout << "\n Parent destructor called\n" << endl;
}
};
class Child : public Parent
{
public:
Child () //Ctor
{
cout << "\nChild constructor called\n" << endl;
}
~Child() //dtor
{
cout << "\nChild destructor called\n" << endl;
}
};
Parent* get() {
return new Child();
}
int main(int argc, char const* argv[])
{
Parent * p1 = get(); // this is ok
std::unique_ptr<Parent> p2(get()); // this is not ok
return 0;
}
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我正在尝试将 unique_ptr 与 Parent 类一起使用。但是编译器抛出了错误
/usr/include/c++/5/bits/unique_ptr.h: In instantiation
of ‘void std::default_delete<_Tp>::operator()(_Tp*) const
[with _Tp = Parent]’:
/usr/include/c++/5/bits/unique_ptr.h:236:17: required
from ‘std::unique_ptr<_Tp, _Dp>::~unique_ptr() [with _Tp
= Parent; _Dp = std::default_delete<Parent>]’
main.cpp:38:35: required from here
main.cpp:12:5: error: ‘Parent::~Parent()’ is protected
~ Parent() //Dtor
^
In file included from /usr/include/c++/5/memory:81:0,
from main.cpp:2:
/usr/include/c++/5/bits/unique_ptr.h:76:2: error: within
this context
delete __ptr;
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关于摆脱这个问题的任何想法?我无法破解父子类,因为它们是第三方库的类。
您可以结交std::default_delete<Parent>朋友Parent来修复该错误。并且您可能还希望在通过指针访问派生类~Parent virtual时避免未定义的行为。deleteParent
例如:
class Parent {
friend class std::default_delete<Parent>;
// ...
protected:
virtual ~Parent();
// ...
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但是,Parent设计清楚地表明您不应该delete通过Parent指针,这就是析构函数是非公开的。阅读Virtuality了解更多详情:
准则#4:基类析构函数应该是public 和virtual,或者protected 和nonvirtual。
你可能想引入另一个中间基类来解决这个问题:
class Parent { // Comes from a 3rd-party library header.
protected:
~Parent();
};
struct MyParent : Parent { // The intermediate base class.
virtual ~MyParent();
};
class Derived : public MyParent {};
std::unique_ptr<MyParent> createDerived() {
return std::unique_ptr<MyParent>(new Derived);
}
int main() {
auto p = createDerived();
}
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