bla*_*ury 4 schema json dataframe pyspark
我在 json 文件中为 df 定义了我的架构,如下所示:
{
"table1":{
"fields":[
{"metadata":{}, "name":"first_name", "type":"string", "nullable":false},
{"metadata":{}, "name":"last_name", "type":"string", "nullable":false},
{"metadata":{}, "name":"subjects", "type":"array","items":{"type":["string", "string"]}, "nullable":false},
{"metadata":{}, "name":"marks", "type":"array","items":{"type":["integer", "integer"]}, "nullable":false},
{"metadata":{}, "name":"dept", "type":"string", "nullable":false}
]
}
}
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EG JSON 数据:
{
"table1": [
{
"first_name":"john",
"last_name":"doe",
"subjects":["maths","science"],
"marks":[90,67],
"dept":"abc"
},
{
"first_name":"dan",
"last_name":"steyn",
"subjects":["maths","science"],
"marks":[90,67],
"dept":"abc"
},
{
"first_name":"rose",
"last_name":"wayne",
"subjects":["maths","science"],
"marks":[90,67],
"dept":"abc"
},
{
"first_name":"nat",
"last_name":"lee",
"subjects":["maths","science"],
"marks":[90,67],
"dept":"abc"
},
{
"first_name":"jim",
"last_name":"lim",
"subjects":["maths","science"],
"marks":[90,67],
"dept":"abc"
}
]
}
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我想从这个 json 文件创建等效的 spark 模式。下面是我的代码:(参考:从 json 模式表示创建 spark 数据帧模式)
with open(schemaFile) as s:
schema = json.load(s)["table1"]
source_schema = StructType.fromJson(schema)
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如果我没有任何数组列,上面的代码工作正常。但是,如果我的架构中有数组列,则会引发以下错误。
“无法解析数据类型:数组”(“无法解析数据类型:%s”json_value)
在您的情况下,数组的表示存在问题。正确的语法是:
{ "metadata": {},
"name": "marks",
"nullable": true, "type": {"containsNull": true, "elementType": "long", "type": "array" } }
.
为了从 json 检索架构,您可以编写下一个 pyspark 代码段:
jsonData = """{
"table1": [{
"first_name": "john",
"last_name": "doe",
"subjects": ["maths", "science"],
"marks": [90, 67],
"dept": "abc"
},
{
"first_name": "dan",
"last_name": "steyn",
"subjects": ["maths", "science"],
"marks": [90, 67],
"dept": "abc"
},
{
"first_name": "rose",
"last_name": "wayne",
"subjects": ["maths", "science"],
"marks": [90, 67],
"dept": "abc"
},
{
"first_name": "nat",
"last_name": "lee",
"subjects": ["maths", "science"],
"marks": [90, 67],
"dept": "abc"
},
{
"first_name": "jim",
"last_name": "lim",
"subjects": ["maths", "science"],
"marks": [90, 67],
"dept": "abc"
}
]
}"""
df = spark.read.json(sc.parallelize([jsonData]))
df.schema.json()
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这应该输出:
{
"fields": [{
"metadata": {},
"name": "table1",
"nullable": true,
"type": {
"containsNull": true,
"elementType": {
"fields": [{
"metadata": {},
"name": "dept",
"nullable": true,
"type": "string"
}, {
"metadata": {},
"name": "first_name",
"nullable": true,
"type": "string"
}, {
"metadata": {},
"name": "last_name",
"nullable": true,
"type": "string"
}, {
"metadata": {},
"name": "marks",
"nullable": true,
"type": {
"containsNull": true,
"elementType": "long",
"type": "array"
}
}, {
"metadata": {},
"name": "subjects",
"nullable": true,
"type": {
"containsNull": true,
"elementType": "string",
"type": "array"
}
}],
"type": "struct"
},
"type": "array"
}
}],
"type": "struct"
}
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或者,您可以使用df.schema.simpleString()
它返回一个相对简单的模式格式:
struct<table1:array<struct<dept:string,first_name:string,last_name:string,marks:array<bigint>,subjects:array<string>>>>
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最后,您可以将上面的架构存储到一个文件中,然后使用以下命令加载它:
import json
new_schema = StructType.fromJson(json.loads(schema_json))
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正如你所做的那样。请记住,您也可以为任何 json 数据动态地实现所描述的过程。
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