如何在Qt(或PyQt)中将一个主窗口调用到另一个主窗口

Question

在我的项目中,我创建了两个主窗口,我想从mainwindow1(运行中)调用mainwindow2.在mainwindow1我已经使用app.exec_()(PyQt)并显示maindow2我在按钮的click事件中使用maindow2.show()但没有显示任何内容

Answer 1

调用mainwindow2.show()应该适合你.你能给出一个更完整的代码示例吗？其他地方可能有问题.

编辑: 更新代码以显示打开和关闭其他窗口时如何隐藏和显示窗口的示例.

from PyQt4.QtGui import QApplication, QMainWindow, QPushButton, \
            QLabel, QVBoxLayout, QWidget
from PyQt4.QtCore import pyqtSignal

class MainWindow1(QMainWindow):
    def __init__(self, parent=None):
        QMainWindow.__init__(self, parent) 
        button = QPushButton('Test')
        button.clicked.connect(self.newWindow)
        label = QLabel('MainWindow1')

        centralWidget = QWidget()
        vbox = QVBoxLayout(centralWidget)
        vbox.addWidget(label)
        vbox.addWidget(button)
        self.setCentralWidget(centralWidget)

    def newWindow(self):
        self.mainwindow2 = MainWindow2(self)
        self.mainwindow2.closed.connect(self.show)
        self.mainwindow2.show()
        self.hide()

class MainWindow2(QMainWindow):

    # QMainWindow doesn't have a closed signal, so we'll make one.
    closed = pyqtSignal()

    def __init__(self, parent=None):
        QMainWindow.__init__(self, parent)
        self.parent = parent
        label = QLabel('MainWindow2', self)

    def closeEvent(self, event):
        self.closed.emit()
        event.accept()

def startmain():
    app = QApplication(sys.argv)
    mainwindow1 = MainWindow1()
    mainwindow1.show()
    sys.exit(app.exec_())

if __name__ == "__main__":
    import sys
    startmain()