use*_*295 16 java generics java-8 java-stream collectors
我如何使用收集器将DAO列表转换为 Map<String, List<Pojo>>
daoList看起来像这样:
[0] : id = "34234", team = "gools", name = "bob", type = "old"
[1] : id = "23423", team = "fool" , name = "sam", type = "new"
[2] : id = "34342", team = "gools" , name = "dan", type = "new"
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我想对“团队”属性进行分组,并为每个团队提供一个列表,如下所示:
"gools":
["id": 34234, "name": "bob", "type": "old"],
["id": 34342, "name": "dan", "type": "new"]
"fool":
["id": 23423, "name": "sam", "type": "new"]
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Pojo看起来像这样:
@Data
@NoArgsConstructor
@AllArgsConstructor(access = AccessLevel.PUBLIC)
public class Pojo{
private String id;
private String name;
private String type;
}
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这就是我试图这样做的方式,显然是错误的方式:
public Team groupedByTeams(List<? extends GenericDAO> daoList)
{
Map<String, List<Pojo>> teamMap= daoList.stream()
.collect(Collectors.groupingBy(GenericDAO::getTeam))
}
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Era*_*ran 15
您当前的收集器- .collect(Collectors.groupingBy(GenericDAO::getTeam))正在生成Map<String,List<? extends GenericDAO>>。
为了生成Map<String, List<Pojo>>,您必须通过将收集器链接到收集器将您的GenericDAO实例转换为Pojo实例:Collectors.mapping()Collectors.groupingBy()
Map<String, List<Pojo>> teamMap =
daoList.stream()
.collect(Collectors.groupingBy(GenericDAO::getTeam,
Collectors.mapping (dao -> new Pojo(...),
Collectors.toList())));
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这是假设您有一些Pojo接收GenericDAO实例或相关GenericDAO属性的构造函数。
使用mapping如:
public Map<String, List<Team>> groupedByTeams(List<? extends GenericDAO> daoList) {
Map<String, List<Team>> teamMap = daoList.stream()
.collect(Collectors.groupingBy(GenericDAO::getTeam,
Collectors.mapping(this::convertGenericDaoToTeam, Collectors.toList())));
return teamMap;
}
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这样的转换convertGenericDaoToTeam可能像这样:
Team convertGenericDaoToTeam(GenericDAO genericDAO) {
return new Team(genericDAO.getId(), genericDAO.getName(), genericDAO.getType());
}
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