即时通讯使用Mysql 5.1并给出一个表customer with customerid,paymentdate我需要所有客户的最新付款.所以带有条目的表
row, customerid, paymentdate
1 5 2011-03-01
2 5 2011-04-01
3 6 2011-01-01
4 7 2011-01-01
5 7 2011-02-01
Run Code Online (Sandbox Code Playgroud)
应该返回2,3,5行查询
select max(paymentdate),customerid from payments where customerid=5;
Run Code Online (Sandbox Code Playgroud)
工作,我试图进入某种WHERE客户IN(...),但没有运气,因为它返回2列不仅1
谢谢
最后,答案激发了我找到相关信息并通过以下查询解决了问题(如文章评论中所述)
select * from (select * from payments order by paymentdate desc) as p group by customerid;
Run Code Online (Sandbox Code Playgroud)
你应该group by
是customerid.
select max(paymentdate),customerid from payments group by customerid;
Run Code Online (Sandbox Code Playgroud)
归档时间: |
|
查看次数: |
1369 次 |
最近记录: |