Can someone explain to me why the Python interpreter evaluates this expression to be False?
1 in [1] == True
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I would expect that 1 in [1] would evaluate to True, and obviously True == True would be True. However this isn't what happens - the expression is False. Why does this happen?
int*_*jay 11
==并且in都是比较运算符。并且当您有多个这样的比较运算符时,Python会将其视为链式比较。例如,1 < x < 10等效于1 < x and x < 10。
就您而言,1 in [1] == True等于(1 in [1]) and ([1] == True),其结果为False。
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