Sah*_*rma 0 django django-templates django-models django-views
我正在做一个项目,管理员可以将团队分配给经理。但它不起作用,我不知道它将如何工作。因为它引发了一个错误,指出“精确查找的 QuerySet 值必须限制为使用切片的一个结果。”
这是我的model.py
class manager(models.Model):
name = models.CharField(max_length= 500)
designation = models.CharField(max_length= 500)
user = models.ForeignKey(User,on_delete=models.CASCADE)
class Meta:
permissions = [
("edit_task", "can edit the task"),
]
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这是我的经理团队的 views.py 文件
@login_required (login_url= 'have the url where it will go')
@permission_required('have the permission that is assigned by me')
def supervisor(request):
return render(request, 'manager/index-3.html')
def supervisor_team(request):
print(request.user.email)
email=request.user.email
obj= Create_Team.objects.filter(status='Accept',
managers=manager.objects.filter(user__email=email))
return render(request, "manager/accept_team.html", {"object": obj})
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这是我的模板
<div class="body table-responsive">
<table class="table table-hover">
<thead>
<tr>
<th>S No.</th>
<th>COMPANY NAME</th>
<th>TEAM MEMBER</th>
<th>EMAIL</th>
</tr>
</thead>
<tbody>
{%for object in team%}
<tr>
<form id="form_id" method="POST" action = "#">
{% csrf_token %}
<th scope="row"> {{ forloop.counter }}</th>
<td>{{object.company_name}}</td>
<td>{{object.team_member}}</td>
<td>{{object.email}}</td>
<td>
</tr>
{% endfor %}
</tbody>
</table>
</div>
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我认为这是问题所在:
obj= Create_Team.objects.filter(status='Accept',
managers=manager.objects.filter(user__email=email))
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如果您想按一位经理进行过滤,则必须使用get而不是filter:
obj= Create_Team.objects.filter(status='Accept',
managers=manager.objects.get(user__email=email))
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但是,如果您想按多个经理进行过滤,则需要使用__in:
obj= Create_Team.objects.filter(status='Accept',
managers__in=manager.objects.filter(user__email=email))
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此外,您正在传递{"object": obj})给模板,但在 templare 中,您正在尝试迭代team. 因此将其更改为传递team变量:
return render(request, "manager/accept_team.html", {"team": obj})
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