Ash*_*ver 4 python loops dataframe pandas
我想根据两列中的值从数据框中删除重复的行:Column1和Column2
如果dataframe是:
df = pd.DataFrame({'Column1': ["'cat'", "'toy'", "'cat'"],
'Column2': ["'bat'", "'flower'", "'bat'"],
'Column3': ["'xyz'", "'abc'", "'lmn'"]})
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关于使用:
result_df = df.drop_duplicates(subset=['Column1', 'Column2'], keep='first')
print(result_df)
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我得到:
Column1 Column2 Column3
0 'cat' 'bat' 'xyz'
1 'toy' 'flower' 'abc'
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但是使用相同的代码dataframe(Cat 和 Bat 案例已更改)
df = pd.DataFrame({'Column1': ["'Cat'", "'toy'", "'cat'"],
'Column2': ["'Bat'", "'flower'", "'bat'"],
'Column3': ["'xyz'", "'abc'", "'lmn'"]})
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我得到:
Column1 Column2 Column3
0 'Cat' 'Bat' 'xyz'
1 'toy' 'flower' 'abc'
2 'cat' 'bat' 'lmn'
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预期输出:
Column1 Column2 Column3
0 'cat' 'bat' 'xyz'
1 'toy' 'flower' 'abc'
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这种比较如何不区分大小写?
我想到了。创建新的大写列,然后使用它们删除重复项。完成后,删除大写列。
df = pd.DataFrame({'Column1': ["'Cat'", "'toy'", "'cat'"],
'Column2': ["'Bat'", "'flower'", "'bat'"],
'Column3': ["'xyz'", "'abc'", "'lmn'"]})
df['Column1_Upper'] = df['Column1'].astype(str).str.upper()
df['Column2_Upper'] = df['Column2'].astype(str).str.upper()
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这给出:
+---+---------+----------+---------+---------------+---------------+
| | Column1 | Column2 | Column3 | Column1_Upper | Column2_Upper |
+---+---------+----------+---------+---------------+---------------+
| 0 | 'Cat' | 'Bat' | 'xyz' | 'CAT' | 'BAT' |
| 1 | 'toy' | 'flower' | 'abc' | 'TOY' | 'FLOWER' |
| 2 | 'cat' | 'bat' | 'lmn' | 'CAT' | 'BAT' |
+---+---------+----------+---------+---------------+---------------+
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最后,运行以下命令删除重复项和创建的列。
result_df = df.drop_duplicates(subset=['Column1_Upper', 'Column2_Upper'], keep='first')
result_df.drop(['Column1_Upper', 'Column2_Upper'], axis=1, inplace=True)
print(result_df)
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这给出:
+-----------------------------+
| Column1 Column2 Column3 |
+-----------------------------+
| 0 'Cat' 'Bat' 'xyz' |
| 1 'toy' 'flower' 'abc' |
+-----------------------------+
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